Study guides

Q: Must choose a number between 61 and 107 that is a multiple of 468?

Write your answer...

Submit

Related questions

Good luck. The LCM is 290.

80

80 adn 100

Each of these is correct: 54, 63, 72, 81 and 90.

60 & 80

84 Because 6 is a multiple of 3, 3 doesn't really count. 6 times 7 is 42. a multiple of 42 that is between 61 and 107 is 84. That is why 84 is the answer.

If 245 is a factor, and it is between 200 and 300, then the number must be 245 - provided it is a multiple of 7, which it is.

To be a multiple of 4, 10 and 20 the number must be a multiple of their lowest common multiple. lcm(4, 10, 20) = 20 What is required is a multiple of 20 between 61 and 107. The numbers 80 and 100 both satisfy the problem of being between 61 and 107 and being a multiple of 4, 10 and 20.

To be a multiple of 6 a number must be even and a multiple of 3.356 is not a multiple of three. The short cut to that is if the digits add up to a multiple of three then the original number is a multiple of 3.

yes exept for the numbers 3,9,15,21,27,33 etc

Multiple-choice, also known as "multiple guess".

As w and w are the same number, there are no numbers between w and w. However, if it is inclusive of the limits, (ie "between w and w inclusive"), then there is only 1 number w, which to be a multiple of 4 6 and 8 must be a multiple of their lowest common multiple (lcm) which is 24; ie all multiples of 24, namely w is one of: 24, 48, 72, 96, 120, 144, 168, ...

No number that is a multiple of 3, can be a prime number. A prime number must only be divisible by itself and 1. It cannot be divisible by any other number. Therefore if it is a multiple of 3, then it must be divisible by 3 and hence, not a prime number.

no, but if you choose to change between over and around the wicket (ie which side of the stumps you bowl from) or if you choose to bowl with the other arm, you must notify the umpire before the delivery and he will notify the batsman

No. To be a multiple the number must be able to be divided evenly by the other number. 8/5 = 1.6 (which is not a whole number).

No it is not. To be a multiple of a certain number, the first criterion is that the number must be greater than or equal to the number it is a multiple of. Since 7 is smaller than 48, 7 cannot be a multiple of 48.

If a number, when divided by 6, is more than 5, then the number must be greater than 30 and so cannot be between 29 and 30.

The minimum number of core sports a host Commonwealth Games city must choose is seven.

840 Since it is a multiple of an even number, it must also be even and since it is a multiple of 5 it must be a multiple of 10 (only even multiple of 5).

No, in order for the number to be even, the last number must be a multiple of 2. It doesn't matter what the largest number is as long as the last number is a multiple of two.

No. To be a multiple of 6, it must pass both the tests for being a multiple of 2 and 3. To be a multiple of 2, the number must be even; 9283 is odd, so is not a multiple of 2 and so it not a multiple of 6.

Divide it by 6 and if 6 goes into it with no remainer then it must be a multiple of 6.

In any number pair where one of the numbers is a multiple of the other, that number is the LCM.

In order for the day to fall on the same weekday, the number of years plus the number of leap days between the dates must be a multiple of seven. The number of years is 30, and the number of leap days is 8. 38 in not a multiple of 7.

The prime factorization of 32 is 2x2x2x2x2 or 25. The prime factorization of 40 is 2x2x2x5 or 23x5. For a number to be a multiple of a given number the multiple must have the entire prime factorization of that number in is. So a multiple of 32 must contain 2x2x2x2x2 or 25 . Likewise a multiple of 40 must contain 2x2x2x5 or 23x5. The least number that this could possible happen with must have 5 factors of 2 and one factor of 5 (the highest exponent on each individual prime factor). Thus the LCM is 2x2x2x2x2x5 or 25x5 Which is 160.