endothermic
N2 + 3F2 ==> 2NF32N, 6F on each side of the equation. It can help to create a table system for more complex equations.
If: n2 = 19 Then: n = the square root of 19.
y = kn / (1 + n2)First, let's express it with negative exponents:y = kn * (1 + n2)-1Then apply the chain rule:dy|dn = k(1 + n2)-1 - kn(1 + n2)-2 * 2nAnd simplify:dy|dn = k / (1 + n2) - 2n / kn(1 + n2)
n2 = 20 + n so n2 - n - 20 = 0 that is (n - 5)(n + 4) = 0 so that n - 5 = 0 or n + 4 = 0 n = 5 or n = -4
endothermic
H2CN2 + heat --> N2 + CH2
2co + 2no -> 2co2 + n2
CH4 + 2O2 📷 CO2 + 2H2O + Heat
Four ammonia plus five oxygen molecules yields 4 nitrous oxide plus six water.
more N2 and O2 would form
2H2 + 2NO --> 2H2O + N2
68kj
6
N2(g) + O2(g) 2NO(g)Adding NO would push the reaction to the left, toward the reactants. This is according to Le Chatelier.
kp66
N2 + o2 ----> 2no