12 g NF3 equals 0,17 moles.
The decomposition of nitrogen trifluoride (NF3) can be represented by the following equation: 2 NF3 -> N2 + 3 F2.
NF3 is the correct formula for nitrogen trifluoride.
Here's a tip. If you're writing anything except a recipe and it looks like it has flour in it, you've spelled it wrong. This is true whether you're talking about "flourescent" lights or "flouridation" of water.The formula for nitrogen trifluoride is NF3.
The balanced chemical equation for the decomposition of nitrogen trifluoride (NF3) is 2NF3 → N2 + 3F2. This reaction involves breaking down NF3 into nitrogen gas (N2) and fluorine gas (F2) through decomposition.
To find the mass percent of nitrogen in NF3, you need to calculate the molar mass of NF3 and then determine the mass of nitrogen in one mole of NF3. The molar mass of NF3 is 71.001 g/mol. The molar mass of nitrogen in NF3 is 14.007 g/mol. Therefore, the mass percent of nitrogen in NF3 is (14.007 g/mol / 71.001 g/mol) * 100% ≈ 19.76%.
NF3
The covalent compound of NF3 is called nitrogen trifluoride.
The hybridization of NF3 is sp3. This means that the nitrogen atom in NF3 forms four equivalent sp3 hybrid orbitals when it bonds with the three fluorine atoms.
To find the number of moles of NF3 in 850.49 grams, you first need to convert the mass to moles using the molar mass of NF3, which is 71.00 g/mol. Moles of NF3 = 850.49 g / 71.00 g/mol = 11.98 moles.
No, NF3 is not an ionic compound. It is a covalent compound where nitrogen (N) and fluorine (F) atoms share electrons to form bonds. In NF3, there are covalent bonds within the molecule.
sp3