0
Step 1. Divide each by its Atomic Mass.
H 2.4 / 1 = 2.4
S 39 / 32 = 1.21875
O 58.6 / 16 = 3.6625
Step 2. Compare answers, pick smallest one and divide all answers by that smallest.
H 2.4 / 1.21875 = 1.969
S 1.21875 / 1.21875 = 1
O 3.6625 / 1.21875 = 3.005
Step 3. Look at the decimal parts, if they are close to a whole number round to a whole number --- these become subscripts for the formula.
H2SO3
What else can I help you with?
What does an empirical formula show?
the empirical formula of a compound tells you the proportions of the elements in the compound. with that information you can make some inferences about the identity of the compound. for example a compound with an empirical formula CH4 tells us that for every carbon atom there are four hydrogen atoms. this means that the compound is methane because no other hydrocarbon can have these roportions (try drawing the lewis structure for C2H8, which doesnt exist. you cant!)
How do you know if a formula is an empirical formula?
An empirical formula has no data about the structure of a compound.
The combustion data for an unknown compound containing carbon hydrogen and oxygen was analyzed and the empirical formula for the unknown was found to be C3H5O The molar mass of the unknown was found?
To find the molecular formula from the empirical formula (C3H5O) and molar mass, you need to calculate the molar mass of the empirical formula. Then, divide the molar mass of the unknown compound by the molar mass of the empirical formula to get a ratio. Finally, multiply the subscripts in the empirical formula (C3H5O) by this ratio to determine the molecular formula of the unknown compound.
Is F6 and empirical or molecular formula?
F6 refers to the molecular formula of a compound, indicating that it contains six fluorine atoms. An empirical formula represents the simplest whole-number ratio of the elements in a compound; for F6, the empirical formula would be F, as it indicates the presence of fluorine without specifying the number of atoms. Thus, F6 is not an empirical formula, but rather a molecular one.
A compound formed of 0.059 mol hydrogen and 0.94 mol oxygen has a molecular mass of 34.0 gmole What is the molecular formula of this compound?
The molar ratio of hydrogen to oxygen in the compound is 2:1. To find the empirical formula, divide the moles of each element by the smallest number of moles, which is 0.059 mol for hydrogen. This gives a ratio of 1:0.5 for hydrogen and oxygen, which simplifies to the empirical formula H2O. To find the molecular formula, calculate the molecular mass of H2O (18 g/mol) and divide the given molecular mass (34 g/mol) by the empirical formula mass to get the multiplier of 2. So, the molecular formula of the compound is H2O2.
What is the empirical formula of the compound that is 75 carbon and 25 hydrogen?
The empirical formula of a compound is the simplest whole number ratio of the elements in the compound. In C75H25, the ratio of carbon to hydrogen is 75:25, which is equal to 3:1. Thus, the empirical formula is C3H.
Empirical formula CH?
The empirical formula CH indicates that the compound contains one carbon atom (C) and one hydrogen atom (H) in the simplest whole number ratio. It does not provide information about the actual number of atoms present in the compound.
Combustion analysis of toluene a common organic solvent gives 5.86 mg of CO2 and 1.37 mg of H2O If the compound contains only carbon and hydrogen what is its empirical formula?
To find the empirical formula, we first need to convert the mass of CO2 and H2O to moles. From the molar ratios in the products, we find the moles of carbon and hydrogen present. Then, we determine the ratio of carbon to hydrogen atoms, giving the empirical formula as C7H8.
What is the molecular formula of a compound with an empirical formula of CH?
The molecular formula of a compound with an empirical formula of CH is likely to be CH, as there is only one carbon atom and one hydrogen atom in the empirical formula. In this case, the empirical formula is also the molecular formula.
Empirical formula for silver oxide?
Silver oxide is an ionic compound so its molecular and empirical formula is same Ag2O
What is the empirical formula of silicon hydride?
The empirical formula of silicon hydride is SiH4. This formula represents the simplest whole number ratio of silicon to hydrogen atoms in the compound.
What is the EMPERICAL Formula of c4 h10?
The empirical formula of a compound represents the simplest whole-number ratio of atoms present in the compound. For C4H10, there is a common factor of 2 for both carbon and hydrogen, so the empirical formula would be C2H5.
Is NH3 an empirical formula?
Yes, NH3 is an empirical formula. An empirical formula represents the simplest whole-number ratio of atoms in a compound. In the case of ammonia (NH3), the ratio of nitrogen to hydrogen is 1:3, making NH3 the empirical formula.
What does an empirical formula show?
the empirical formula of a compound tells you the proportions of the elements in the compound. with that information you can make some inferences about the identity of the compound. for example a compound with an empirical formula CH4 tells us that for every carbon atom there are four hydrogen atoms. this means that the compound is methane because no other hydrocarbon can have these roportions (try drawing the lewis structure for C2H8, which doesnt exist. you cant!)
How do you know if a formula is an empirical formula?
An empirical formula has no data about the structure of a compound.
What is the relationship between the empirical formula and the molecular formula?
An empirical formula contains the constituent elements in the lowest possible mathematical whole-number ratio. In some cases, this is the legitimate formula for the compound, particularly if the substance you're dealing with is an ionic compound. Sometimes, however, the actual formula, known as the molecular formula, is a whole-number multiple of the empirical formula. The molecular formula for glucose is C6H12O6. However, an empirically-derived formula for glucose would be CH2O, which is the lowest possible ratio of carbon, hydrogen, and oxygen in that compound.
What is the empirical formula for C3H5?
The empirical formula is C3H5. The answer does not change from the given form because there is no common denominator to divide by.
