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Step 1. Divide each by its Atomic Mass.

H 2.4 / 1 = 2.4

S 39 / 32 = 1.21875

O 58.6 / 16 = 3.6625

Step 2. Compare answers, pick smallest one and divide all answers by that smallest.

H 2.4 / 1.21875 = 1.969

S 1.21875 / 1.21875 = 1

O 3.6625 / 1.21875 = 3.005

Step 3. Look at the decimal parts, if they are close to a whole number round to a whole number --- these become subscripts for the formula.

H2SO3

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Q: Need help to find the empirical formula of the compound A compound of sulphur contains 2.4 percent hydrogen 39 percent sulphur and 58.6 percent oxygen Find the empirical formula of the compound?
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