Wiki User
∙ 11y agoStep 1. Divide each by its Atomic Mass.
H 2.4 / 1 = 2.4
S 39 / 32 = 1.21875
O 58.6 / 16 = 3.6625
Step 2. Compare answers, pick smallest one and divide all answers by that smallest.
H 2.4 / 1.21875 = 1.969
S 1.21875 / 1.21875 = 1
O 3.6625 / 1.21875 = 3.005
Step 3. Look at the decimal parts, if they are close to a whole number round to a whole number --- these become subscripts for the formula.
H2SO3
Wiki User
∙ 11y agoAn empirical formula has no data about the structure of a compound.
the empirical formula of a compound tells you the proportions of the elements in the compound. with that information you can make some inferences about the identity of the compound. for example a compound with an empirical formula CH4 tells us that for every carbon atom there are four hydrogen atoms. this means that the compound is methane because no other hydrocarbon can have these roportions (try drawing the lewis structure for C2H8, which doesnt exist. you cant!)
To find the molecular formula from the empirical formula (C3H5O) and molar mass, you need to calculate the molar mass of the empirical formula. Then, divide the molar mass of the unknown compound by the molar mass of the empirical formula to get a ratio. Finally, multiply the subscripts in the empirical formula (C3H5O) by this ratio to determine the molecular formula of the unknown compound.
The empirical formula is representative for the chemical composition of a compound; the structural formula is representative for the spatial structure of the compound.
The molar ratio of hydrogen to oxygen in the compound is 2:1. To find the empirical formula, divide the moles of each element by the smallest number of moles, which is 0.059 mol for hydrogen. This gives a ratio of 1:0.5 for hydrogen and oxygen, which simplifies to the empirical formula H2O. To find the molecular formula, calculate the molecular mass of H2O (18 g/mol) and divide the given molecular mass (34 g/mol) by the empirical formula mass to get the multiplier of 2. So, the molecular formula of the compound is H2O2.
The empirical formula of a compound is the simplest whole number ratio of the elements in the compound. In C75H25, the ratio of carbon to hydrogen is 75:25, which is equal to 3:1. Thus, the empirical formula is C3H.
An empirical formula is the lowest ratio of elements in a compound. So since H2O2 can be reduced to HO (H1O1), that is the empirical formula. The molecular formula is H2O2.
The empirical formula CH indicates that the compound contains one carbon atom (C) and one hydrogen atom (H) in the simplest whole number ratio. It does not provide information about the actual number of atoms present in the compound.
To find the empirical formula, we first need to convert the mass of CO2 and H2O to moles. From the molar ratios in the products, we find the moles of carbon and hydrogen present. Then, we determine the ratio of carbon to hydrogen atoms, giving the empirical formula as C7H8.
The molecular formula of a compound with an empirical formula of CH is likely to be CH, as there is only one carbon atom and one hydrogen atom in the empirical formula. In this case, the empirical formula is also the molecular formula.
The empirical formula for silver oxide is Ag2O, which indicates that the compound contains twice as many silver atoms as oxygen atoms.
The empirical formula of silicon hydride is SiH4. This formula represents the simplest whole number ratio of silicon to hydrogen atoms in the compound.
Yes, NH3 is an empirical formula. An empirical formula represents the simplest whole-number ratio of atoms in a compound. In the case of ammonia (NH3), the ratio of nitrogen to hydrogen is 1:3, making NH3 the empirical formula.
The empirical formula of a compound represents the simplest whole-number ratio of atoms present in the compound. For C4H10, there is a common factor of 2 for both carbon and hydrogen, so the empirical formula would be C2H5.
An empirical formula has no data about the structure of a compound.
the empirical formula of a compound tells you the proportions of the elements in the compound. with that information you can make some inferences about the identity of the compound. for example a compound with an empirical formula CH4 tells us that for every carbon atom there are four hydrogen atoms. this means that the compound is methane because no other hydrocarbon can have these roportions (try drawing the lewis structure for C2H8, which doesnt exist. you cant!)
The empirical formula would be CaBr2 since it contains a ratio of 1 calcium to 2 bromine atoms.