There are 24 trailing zeros in 100 factorial.
122 zeros.
To calculate the number of zeros in a factorial number, we need to determine the number of factors of 5 in the factorial. In this case, we are looking at 10 to the power of 10 factorial. The number of factors of 5 in 10! is 2 (from 5 and 10). Therefore, the number of zeros in 10 to the power of 10 factorial would be 2.
To determine the number of trailing zeros in 85 factorial (85!), you count how many times 5 is a factor in the numbers from 1 to 85, as there are always more factors of 2 than 5. This is calculated using the formula: [ \text{Number of trailing zeros} = \left\lfloor \frac{85}{5} \right\rfloor + \left\lfloor \frac{85}{25} \right\rfloor = 17 + 3 = 20. ] Thus, 85! has 20 trailing zeros.
To determine the number of trailing zeros in (5000!), you can use the formula that counts the number of factors of 5 in the factorial. This is calculated as: [ \left\lfloor \frac{5000}{5} \right\rfloor + \left\lfloor \frac{5000}{25} \right\rfloor + \left\lfloor \frac{5000}{125} \right\rfloor + \left\lfloor \frac{5000}{625} \right\rfloor ] Calculating this gives: [ 1000 + 200 + 40 + 8 = 1248 ] Thus, (5000!) has 1248 trailing zeros.
Exactly as in the question. There is no need for a decimal point and trailing zeros.Exactly as in the question. There is no need for a decimal point and trailing zeros.Exactly as in the question. There is no need for a decimal point and trailing zeros.Exactly as in the question. There is no need for a decimal point and trailing zeros.
122 zeros.
242 zeros.
To calculate the number of zeros in a factorial number, we need to determine the number of factors of 5 in the factorial. In this case, we are looking at 10 to the power of 10 factorial. The number of factors of 5 in 10! is 2 (from 5 and 10). Therefore, the number of zeros in 10 to the power of 10 factorial would be 2.
To determine the number of trailing zeros in 85 factorial (85!), you count how many times 5 is a factor in the numbers from 1 to 85, as there are always more factors of 2 than 5. This is calculated using the formula: [ \text{Number of trailing zeros} = \left\lfloor \frac{85}{5} \right\rfloor + \left\lfloor \frac{85}{25} \right\rfloor = 17 + 3 = 20. ] Thus, 85! has 20 trailing zeros.
One - the trailing zeros are placeholders.
There are 18 zeros.
To determine the number of trailing zeros in (5000!), you can use the formula that counts the number of factors of 5 in the factorial. This is calculated as: [ \left\lfloor \frac{5000}{5} \right\rfloor + \left\lfloor \frac{5000}{25} \right\rfloor + \left\lfloor \frac{5000}{125} \right\rfloor + \left\lfloor \frac{5000}{625} \right\rfloor ] Calculating this gives: [ 1000 + 200 + 40 + 8 = 1248 ] Thus, (5000!) has 1248 trailing zeros.
All digit are significant except: leading zeros,in the case of integers, trailing zeros.All digit are significant except: leading zeros,in the case of integers, trailing zeros.All digit are significant except: leading zeros,in the case of integers, trailing zeros.All digit are significant except: leading zeros,in the case of integers, trailing zeros.
three, leading zeros are not significant and trailing zeros are significant if there is a decimal. trailing zeros are not significant if there is no decimal zeros in the middle of numbers are significant
The question, as asked, is difficult to answer, The number of zeros in factorial 100 is not the same as the number of 0s at the end of factorial 100 since there will be some before the end.The answer to the second question is easy:The number of zeros is determined by the number of 10s in the factors.Since 2s are common, this, in turn, depends on the number of 5s.In 100!, there are 20 multiples of 5 each of which will contribute a 5 to the factors of 100!.In addition there are 4 multiples of 52 = 25 each of which will contribute another 5 to the factors of 100!All in all, therefore, there are 24 5s giving 24 0s at the end of 100!
The trailing zeros make no difference. They could both just be written as 5.3 instead, removing all the trailing zeros.
Leading zeros and trailing zeros in numbers that don't have a decimal point.