To determine the number of trailing zeros in (5000!), you can use the formula that counts the number of factors of 5 in the factorial. This is calculated as:
[ \left\lfloor \frac{5000}{5} \right\rfloor + \left\lfloor \frac{5000}{25} \right\rfloor + \left\lfloor \frac{5000}{125} \right\rfloor + \left\lfloor \frac{5000}{625} \right\rfloor ]
Calculating this gives:
[ 1000 + 200 + 40 + 8 = 1248 ]
Thus, (5000!) has 1248 trailing zeros.
122 zeros.
To calculate the number of zeros in a factorial number, we need to determine the number of factors of 5 in the factorial. In this case, we are looking at 10 to the power of 10 factorial. The number of factors of 5 in 10! is 2 (from 5 and 10). Therefore, the number of zeros in 10 to the power of 10 factorial would be 2.
There are 24 trailing zeros in 100 factorial.
My calculation gave me 2963 hopefully that is right... * * * * * I suggest 501.
832.
There are 18 zeros.
122 zeros.
242 zeros.
To calculate the number of zeros in a factorial number, we need to determine the number of factors of 5 in the factorial. In this case, we are looking at 10 to the power of 10 factorial. The number of factors of 5 in 10! is 2 (from 5 and 10). Therefore, the number of zeros in 10 to the power of 10 factorial would be 2.
There are 24 trailing zeros in 100 factorial.
18 factorial is equal to 6402373705728000 - with three consecutive zeroes at the end.
Ten Zeros
5000
My calculation gave me 2963 hopefully that is right... * * * * * I suggest 501.
832.
One. The zeros are placeholders.
5000 × 7 = 35,000 Therefore, there are three zeroes in the answer.