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Q: Numbers exactly divisible by 20 are also exactly divisible by what other numbers?

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All whole numbers are divisible. If you mean divisible by numbers other than 1 and themselves, the answer is the set of composite numbers.

Prime numbers are not divisible by any numbers other than themselves and 1.

842 is NOT divisible by nine. It is only divisible by these numbers: 1 2 421 and 842.

Numbers for which the sum of the digits is divisible by 9. This is also true for 3. There are other divisibility/multiple tests for other numbers (e.g., numbers that are divisible by 5 end in 5 or 0; numbers whose last two digits are divisible by 4 are divisible by 4)

It doesn't have a numerical answer. If both numbers are even, one will be divisible by the other.

Prime numbers are only divisible by 1 and themselves. So, a prime number cannot be divisible by 10. The only prime number that is divisible by 2 is 2 itself; all other numbers divisible by 2 are not prime numbers.

Some numbers are divisible by a lot of other numbers; some numbers aren't.

Neither of those numbers is divisible by the other.

prime number is a number that could only be divided by itself and one. odd numbers are naturally not divisible by 2 but odd numbers can be divisible by other numbers. one example is 15. 15 is divisible by itself and one but also by 3 and 5.

No, prime numbers are divisible only by themselves and 1. 2005 is also divisible by other numbers such as 5

Numbers that are divisible by 80 are itself and any of its other multiples

No. They are composite because they are divisible by two and other numbers.

1,2,3,4,6,8,12, and the number itself 24 :)

1700 and 2550

5, all other numbers ending in 5 are divisible by 5.

The numbers could be 1700 and 2550.

No, it is divisible by 2,4 and many other numbers.

No, it is divisible by 3 and several other numbers.

No it is divisible by 5 and some other numbers

Itself and any other of its factors.

1, 2 and 3

1, 2, 3, 4, and 6

No. It is the other way round.

1700 and 2550

1700 and 2550