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You are supposed to:

1) Write two equations, one for the number of heads (express it in terms of the number of cows and horses, which of course are expressed as variables), and one for the number of legs (also expressed as an equation in terms of the number of cows and horses.

2) Solve the two equations simultaneously.

Q: On a farm there are three-legged-cows and horses There are total of 105 heads and 392 legs How many three-legged-cows are on the farm?

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On a farm there are chickens and three-legged-cows. There are total of 49 heads and 130 legs. How many chickens are on the farm?

There are 61 horses and 10 chickens on the farm.

27

there are 36 horses and 23 chickens.........

50 horses and 10 chickens

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On a farm there are chickens and three-legged-cows. There are total of 49 heads and 130 legs. How many chickens are on the farm?

There are 61 horses and 10 chickens on the farm.

27

there are 36 horses and 23 chickens.........

50 horses and 10 chickens

There are 42 chickens in the farm.

85 chickens

If all were horses there would be 428 legs. The shortfall of 36 legs represents 18 chickens so there are 89 horses.

If all the animals were horses there would be 360 legs. There is a shortfall of 23 which means 23 cows and therefore 67 horses.

51 horses of which there are 3 cows with 2 heads and three legs or since there are no 3 legged cows there are 60 horses

There are 51 horses and 14 sheep (51*4)+(14*3)=246 51+14=65

If all animals were horses there would be 4 x 59 ie 236 legs. There is a shortage of 25 legs so there are 25 cows (and 34 horses).