Q: On a farm there are chickens and horses There are total of 122 heads and 318 legs How many chickens are on the farm?

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On a farm there are chickens and three-legged-cows. There are total of 49 heads and 130 legs. How many chickens are on the farm?

There are 61 horses and 10 chickens on the farm.

there are 36 horses and 23 chickens.........

There are 42 chickens in the farm.

27

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On a farm there are chickens and three-legged-cows. There are total of 49 heads and 130 legs. How many chickens are on the farm?

There are 61 horses and 10 chickens on the farm.

there are 36 horses and 23 chickens.........

There are 42 chickens in the farm.

27

50 horses and 10 chickens

If all were horses there would be 428 legs. The shortfall of 36 legs represents 18 chickens so there are 89 horses.

If all were horses there would be 4 x 61 ie 244 legs. There is a shortfall of 50 legs ie 25 less four-legged creatures, so there are 36 horses and 25 chickens, giving 144 + 50 legs

Suppose there are x chickens and y cows Then heads => x + y = 64 And Legs => 2x + 3y = 147 2*Heads: 2x +2y = 128 Subtract from Legs: 19 = y Substitute in Heads: x = 45 Answer: 45 chickens.

Answer : 33 horses. Number of Horses (H) + Number of Chickens (C) = 45 therefore C = 45 - H There are 4H horse legs and 2C chicken legs so, 4H + 2C = 156 substituting for C gives :- 4H + 2(45 - H) = 156 4H + 90 - 2H = 156 2H = 156 - 90 = 66 H = 33 There are 33 horses (and 45 - 33 = 12 chickens)

94 three legged cows and 25 chickens.

There are (c) chickens and (h) horses, so c + h = 91 Each chicken has 2 legs, each horse has 4 legs, so 2c + 4h = 246 The quick way to solve this is to multiply the first equation by 2, then subtract it from the second equation - this eliminates the terms involving "c". 2c + 4h = 246 2c + 2h = 182 ........2h = 64 : h = 32, so c = 91 - 32 = 59 There are 59 chickens on the farm (and 32 horses).