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On a farm there are three-legged-cows and chickens there are a total of 119 heads and 332 legs how many three-legged-cows are on the farm?
94 three legged cows and 25 chickens.
On a farm there are horses and chickens There are total of 131 heads and 448 legs How many horses are on the farm?
On a farm there are chickens and three-legged-cows. There are total of 49 heads and 130 legs. How many chickens are on the farm?
On a farm there are three-legged-cows and chickens There are total of 45 heads and 110 legs How many three-legged-cows are on the farm?
Do-it-in-your-head method: If all animals were chickens there would be 90 legs. There are 20 extra legs, each on a cow, so there are 20 cows and therefore 25 chickens.
On a farm there are chickens and three-legged-cows. There are total of 64 heads and 147 legs. How many chickens are on the farm?
Suppose there are x chickens and y cows Then heads => x + y = 64 And Legs => 2x + 3y = 147 2*Heads: 2x +2y = 128 Subtract from Legs: 19 = y Substitute in Heads: x = 45 Answer: 45 chickens.
On a farm there are three legged cows and chickens there are a total of 48 heads and 122 legs how many three legged cows are there?
Do-it-in-your-head method: If all animals were chickens there would be 96 legs. There are 26 extra legs, each on a cow, so there are 26 cows and therefore 22 chickens.
The dairy farm has both cows and chikensThe farm workers counted 50 legs and 18 heads how many cows are in the farm and how many chickens?
7 cows and 11 chickens. Cows have 4 legs. Chickens have 2 legs. (4 legs)(7 cows) + (2 legs)(11 chickens) = 50 legs. 7 cow heads = 11 chicken heads = 18 heads.
On a farm there are three-legged-cows and chickens There are total of 48 heads and 117 legs How many three-legged-cows are on the farm?
There are 21 three-legged cows and 27 chickens on the farm. Let us say the number of cows = A and the number of chickens is B. The equation for heads is: A+B = 48 The equation for legs is: 3A + 2B = 117 (because a cow has 3 legs and a chicken has 2 legs in this question) We can rearrange the equation for heads as follows: A+B = 48 B = 48-A Now we can replace B in the equation for legs with 48-A as follows: 3A + 2(48-A) = 117 ...and solve: 3A + 96 - 2A = 117 A + 96 = 117 A = 21 So we know there are 21 three-legged cows and from earlier, B = 48-A, so B = 48-21 = 27. Therefore there are 27 chickens.
On a farm there are three legged cows and chickens There are a total of 54 heads and 159 legs How many three legged cows are there?
Cows = M Chickens = C M+C=54 3M+2C=159 C=54-M 3M+2(54-M)=159 3M+108-2M=159 M+108=159 M=51 Cows C=3 Chickens
On a farm there are chickens and three-legged-cows there a total of 116 heads and 256 legs how many chickens are on the farm?
There are 24 three-legged cows and 92 chickens on the farm. Let us say the number of cows = A and the number of chickens is B. The equation for heads is: A+B = 116 The equation for legs is: 3A + 2B = 256 (because a cow has 3 legs and a chicken has 2 legs in this question) We can rearrange the equation for heads as follows: A+B = 116 B = 116-A Now we can replace B in the equation for legs with 48-A as follows: 3A + 2(116-A) = 256 ...and solve: 3A + 232 - 2A = 256 A + 232 = 256 A = 24 So we know there are 24 three-legged cows and from earlier, B = 116-A, so B = 116-24 = 92. Therefore there are 92 chickens.
On a farm there are chickens and three-legged-cows There are total of 90 heads and 211 legs How many chickens are on the farm?
Suppose there are x chicken and y cows where x and y are positive integers. Then number of heads : x + y = 90 and number of legs : 2x + 3y = 211 3*Eqn(1) - Eqn(2) gives: x = 59
On a farm there are chickens and three-legged-cows There are a total of 36 heads and 76 legs How many chickens are on the farm?
Chickens = c, Cows = m c+m=36 c=36-m 2c+3m=76 2(36-m)+3m=76 72-2m+3m=76 m=4 c=36-4=32 He has 32 chickens.
On a farm there are chickens and three-legged-cows There are total of 66 heads and 163 legs How many chickens are on the farm?
Chickens (H) + Cows (C) = 66 : so C = 66 - H However there are 2H chickens legs and 3C cows legs : 2H + 3C = 163 Substituting for C gives : 2H + 3(66 - H) = 163 : 2H +198 - 3H = 163 : H = 35. Number of chickens = 35 (and number of cows = 66 - 35 = 31)
