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Clearly, (2272 - 875) = 1397, is exactly divisible by N.

Now, 1397 = 11 x 127

The required 3-digit number is 127, the sum of whose digits is 10.

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Q: On dividing 2272 as well as 875 by 3 digit no N we get the same remainder The sum of the digits of N is?
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