Pythagorean Theorem
a^2 + b^2 = c^2
where c is the hypotenuse
c =sqrt(6^2 + 8^2)
c = sqrt(100)
= 10
A triangle with an hypotenuse has a right angle that measures 90 degrees and two other acute angles,
Using Pythagoras: hypotenuse2 = one_leg2 + other_leg2 ⇒ hypotenuse = √(one_leg2 + other_leg2) = √(212 + 282) = √1225 = 35 units.
my name is bdub and the answer is 5 dubass
Approx 9.6987 cm.
Use Pythagoras: 24 units
A triangle with an hypotenuse has a right angle that measures 90 degrees and two other acute angles,
A right triangle has a hypotenuse of 13 cm and one leg that measures 12 cm What is the length of the other leg?
The hypotenuse is always the longest of the three sides of a right triangle.
The approximate length of the other leg of the triangle is: 11.9 inches.
A right triangle has a hypotenuse of 12cm and a leg that is 9cm the other leg would be 7.94. This is a math problem.
The hypotenuse must be longer than the other other leg.
Using Pythagoras: hypotenuse2 = one_leg2 + other_leg2 ⇒ hypotenuse = √(one_leg2 + other_leg2) = √(212 + 282) = √1225 = 35 units.
a^2 + b^2 = c^2. Therefore, the hypotenuse is (5^2 + 12^2)^1/2
10 inches
This is impossible. A leg cannot be greater than the hypotenuse. (Unless the triangle is part imaginary)
The length of the hypotenuse = √(4^2 + 6^2) = √52 ≈ 7.21 in
my name is bdub and the answer is 5 dubass