Add the exponents: p2p7 = p9
(p-2) x (p5) = p-2+5 = p3
probability of a machine component failing = 2/7 P(at least 4 failed) = P( 4 failed)+P(5 failed) +P(6 failed)+P(7 failed) Using binomial probability: P(4 failed ) =7C4 (2/7)^4 ((5/7)^3 = 0.084987 P(5 failed) = 7C5 (2/7)^5 (5/7)^2 = 0.020395 P(6 failed ) = 7C6 (2/7)^6 (5/7) = 0.002719 P(7 failed) = (2/7)^7 = 0.000155 Adding, P(at least 4 failures) = 0.108257
The Answer Is 120 :P -Kris
p=1/3(A)^2 where: p=power A=maximun amplitude
3p
Area: A = l2 Where l is the length of a side. and the 2 means raised to the second power "squared" which means multiplied times itself.
The formula to find the perimeter of a rectangle is: P = 2L + 2W, where 2L is the length multiplied by 2 and 2W is the width multiplied by 2. Hence: P = 2*10 + 2*5 P = 20 + 10 P = 30
what is p multiplied by 4
(p-2) x (p5) = p-2+5 = p3
10 to the power of 23 = 100 000 000 000 000 000 000 000 So 3.3022 multiplied by that = 330 220 000 000 000 000 000 000 Which would be said as 330 thousand 220 quintillion. (I think :P)
times one <P> <P>Any number multiplied by 1 will be itself. <P>1x2=2 <P>1x3=3 <P>and so on</P>
7
The Answer Is 120 :P -Kris
probability of a machine component failing = 2/7 P(at least 4 failed) = P( 4 failed)+P(5 failed) +P(6 failed)+P(7 failed) Using binomial probability: P(4 failed ) =7C4 (2/7)^4 ((5/7)^3 = 0.084987 P(5 failed) = 7C5 (2/7)^5 (5/7)^2 = 0.020395 P(6 failed ) = 7C6 (2/7)^6 (5/7) = 0.002719 P(7 failed) = (2/7)^7 = 0.000155 Adding, P(at least 4 failures) = 0.108257
2*p*.707 because P=C*f*V2 f has been multiplied by 2 but that doubling in frequency also changes the capacitive impedance by a factor of (1 divided by the square root of 2).
P=2(l+w) P=2(7+3) P=2(10) P=20
p=1/3(A)^2 where: p=power A=maximun amplitude