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Parentheses before -1 and after 3x and before 3 and after 3x What is the answer to -2 cos2 3x-3 sin 3x equals 0?
Wiki User
∙ 12y ago
I think you mean to solve:
(-2 cos23x) - (3 sin 3x) = 0
cos2 x + sin2 x = 1
⇒ cos2x = 1 - sin2 x
⇒ -2 cos2 3x - 3 sin 3x = -2(1 - sin2 3x) - 3 sin 3x = 0
⇒ 2 sin2 3x - 3 sin 3x - 2 = 0
⇒ (2 sin 3x + 1)(sin 3x - 2) = 0
⇒ sin 3x = -1/2 or 2
sin 3x = 2 is impossible as the range of sine is -1 ≤ sine ≤ 1
Thus:
sin 3x = -1/2
⇒ 3x = 2nπ - π/6 or 2nπ - 5π/6
⇒ x = 2/3nπ -π/18 or 2/3nπ -5π/18
Wiki User
∙ 12y ago
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Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y2 of (x + y)2. There is no operator between 3x3 and x2 (which I assume are 3x-cubed and x-squared).
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y
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