The 5 ways to prove that two triangles are congruent are to find equal: 1) side-side-side 2) side-angle-side 3) angle-side-angle 4) angle-angle-angle 5) hypotenuse-leg
YES ... to prove it, divide both the numerator and the denominator of 5/15 by 5 and you will get 1/3
Oh, dude, obtuse angles are like those chill angles that are greater than 90 degrees but less than 180 degrees. So, shapes like obtuse triangles, obtuse trapezoids, and obtuse pentagons totally rock those angles. Just imagine them lounging around, being all nonchalant and stuff.
Each angle is 180/5 = 36 degrees
Five. It is a regular pentagon.
You have to prove it by showing what the mean of the five numbers is. First, you add up the five numbers, which is equal to 15. Then, you divide the sum by 5, which is 3, and not 8.
The measure of an exterior angle of an equiangular pentagon is 72 degrees. An equiangular pentagon is a regular pentagon that has five equal sides and five equal angles. An interior angle of a pentagon is equal to 108 degrees.
An angle of thirty-five degrees, and any angle less than 90 degrees is an acute angle.
360 degrees / 5 pieces = 72 degrees
I am picturing two parallel lines with a transversal, If Angle two and five are corresponding then they are congruent. If they are not corresponding then they would be supplementary.
A five right angle turn is 450 degress. It ia an ubtuse angle, which means it ia greater than a right angle, 90 degress.
SSS, SAS, ASA, AAS, RHS. SSA can prove congruence if the angle in question is obtuse (if it's 90 degrees, then it's exactly equivalent to RHS).