Prove the existence of triangles

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โˆ™ 2012-05-17 11:17:21

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1. Given any line, there are at least two points on the line. Call them A and B.

2. Given any line, there exists at least one point in the plane that is not on the line. Call that point C.

3. Given any two points (A and C and, then B and C) there exists a straight line joining them.

The point C is not on AB so AB and AC are distinct. Similarly, AB and BC are distinct so that there are three lines that meet, in pairs, at three vertices - and that is a triangle.

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โˆ™ 2012-05-17 11:17:21
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