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Ron will use all 900 meters of fence and wants to enclose a rectangular region that contain four rectangular pens within it what will be the area for each pen?
Wiki User
∙ 13y ago
My drawing shows this equation. (A = XY--remember this! )
5X + 2Y = 900
solve for Y
Y = ( 900 - 2X)/2
substitute back in; remember X*Y
5X(900 - 2X)/2
4500X - 10X^2/2
2250X - 5X^2
d/dx( 2250X - 5X^2)
2250 - 10X
2250 = 10X
X = 225
as you see 900/4 is 225, so this is the optimal area for each pen
Wiki User
∙ 13y ago
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