Magnitude of average acceleration = (change of speed) divided by (time for the change)
Average 'A' = (6 - 4) / 20 = 2/20 = 0.1 meter per second2
-- That's the average over the 20 seconds. We don't know anything about the
value of the acceleration at any particular instant during the 20 seconds.
-- We're working entirely with scalars ... speed, not velocity, and magnitude of
acceleration ... since we don't know anything about the runner's direction at
any time during the whole event.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
Acceleration = Change in Velocity / Change in Time a = (Final Velocity - Initial Velocity) / (Final Time - Initial Time) = (55-0)/(5-0) = 55/5 a = 11 m/s^2
You need more details.The final velocity could be 0However, you need to know the initial velocity, and the braking acceleration, and perhaps other acceleration/deceleration factors to know the true answer.
It depends on what the initial velocity was. If it was 0, then: 11-0 = 2.2 m/s squared 5
Data is insufficient. initial velocity is 0. final velocity is 30 mph. Need acceleration to use the formula v = u + at.
That depends on its initial velocity and its acceleration. V1 = V0 + a * t
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
To calculate velocity using acceleration, start by multiplying the acceleration by the change in time. For example, if the acceleration is 10 m/s2 and the change in time is 5 seconds, then there is a 50 m/s increase in velocity. Then, add the initial velocity to the increase in velocity.
Acceleration = Change in Velocity / Change in Time a = (Final Velocity - Initial Velocity) / (Final Time - Initial Time) = (55-0)/(5-0) = 55/5 a = 11 m/s^2
the final velocity = initial velocity + acceleration x time; since acceleration is negative final velocity = 45 - 10x3 = 45 -30 = 15 mph
You need more details.The final velocity could be 0However, you need to know the initial velocity, and the braking acceleration, and perhaps other acceleration/deceleration factors to know the true answer.
It will depend upon the initial velocity of the body. If 'u' be the initial velocity of the body, then the final velocity will be: v = u + at (v = final velocity, a = acceleration, t = time) i.e., v=u+10*7 = (u + 70) m/sec. If u=0 (i.e the initial velocity be zero) then final velocity, v=70 m/sec.
Linear Velocity = Initial Velocity (m/s) + Acceleration (m/s2) * t 43.2 km/h
I'm assuming you are not talking about constant acceleration, which in itself iscontinuous. If you are talking about constant (meaning it's just a number, and not a function itself) acceleration, than just use the formula:v = i + at, wherev = velocity, i = initial velocity, a = acceleration, and t = timeOtherwise, you need to have some calculus knowledge. A velocity function is just the antiderivative (integral) of an acceleration function.Say, acceleration was given as:a = 2ttake the integral of thatv =∫ 2t dt = (2/2)t2+c =t2+cIn this case, the c is the initial velocity.Example:An object moves with an acceleration determined by a=t+3 (in m/s^2). Find the velocity of the object after 10 seconds have passed, given that the object has an initial velocity of 2 m/s.a = t + 3v =∫( t + 3) dt = (1/2)t2 + 3t + c, with c being initial velocityv(10 seconds) = (1/2)(10)2 + 3(10) + (2) = 82 m/s
Using the acceleration formula, final acceleration is the final velocity minus the initial velocity over elapsed time. Final velocity you gave as 40m/s, and the initial velocity was zero (the apple was stationary on the tree), so the difference is 40 m/s. Divided by the time you gave, 4 s, this will be 10 m/sĀ²
It depends on what the initial velocity was. If it was 0, then: 11-0 = 2.2 m/s squared 5