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What is the acceleration speed if you go from standing still to running 11 ms in 5 seconds?
The average rate of acceleration is (11/5) = 2.2 m/sec2 .
A skydiver slows down from 65 ms to 5 ms by opening the parachute If this takes 0.75 seconds what is the skydivers acceleration?
80 m/s2 up
A motorcycle speeds up from 10 ms to 25 ms in 5 seconds What is the motorcycle's acceleration?
The average acceleration during any interval is (change in speed) divided by (time for the change).A = (25 - 10)/5 = 15/5 = 3 meters per second2
Skydiver slows down from 65 ms to 5 ms by opening the parachute If this takes 0.75 seconds what is the skydiver's acceleration?
80 m/s 2 up
What is the acceleration of a ball that starts from rest and rolls down a ramp and gains speed at 25 ms in 5 seconds?
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
What is the acceleration speed if you go from standing still to running 11 ms in 5 seconds?
The average rate of acceleration is (11/5) = 2.2 m/sec2 .
The velocity of a car changes from 20 ms east to 5 ms east in 5 seconds. What is the acceleration of the car?
To find the acceleration, we use the formula ( a = \frac{\Delta v}{\Delta t} ), where ( \Delta v ) is the change in velocity and ( \Delta t ) is the change in time. The change in velocity ( \Delta v ) is ( 5 , \text{ms}^{-1} - 20 , \text{ms}^{-1} = -15 , \text{ms}^{-1} ). Over the time interval of 5 seconds, the acceleration is ( a = \frac{-15 , \text{ms}^{-1}}{5 , \text{s}} = -3 , \text{ms}^{-2} ). Thus, the car's acceleration is ( -3 , \text{ms}^{-2} ), indicating it is decelerating.
A skydiver slows down from 65 ms to 5 ms by opening the parachute If this takes 0.75 seconds what is the skydivers acceleration?
80 m/s2 up
A motorcycle speeds up from 10 ms to 25 ms in 5 seconds What is the motorcycle's acceleration?
The average acceleration during any interval is (change in speed) divided by (time for the change).A = (25 - 10)/5 = 15/5 = 3 meters per second2
Skydiver slows down from 65 ms to 5 ms by opening the parachute If this takes 0.75 seconds what is the skydiver's acceleration?
80 m/s 2 up
A rock dropped on the moon will increase its speed from 0 ms to 8.15 ms in about 5 seconds. What is the acceleration of the rock?
The acceleration of the rock can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values, we get acceleration = (8.15 m/s - 0 m/s) / 5 s = 1.63 m/s^2.
A runner can accelerate from standing still to running 11 m per sec in 5 seconds What is her acceleration?
The runner's acceleration can be calculated using the formula a = Δv/t, where Δv is the change in velocity (11 m/s - 0 m/s = 11 m/s) and t is the time taken (5 seconds). Therefore, the acceleration is 11 m/s divided by 5 seconds, which equals 2.2 m/s².
When rock dropped on the moon will increase its speed from 0 ms to 8.15 ms in about 5 seconds what is the acceleration of the rock?
The acceleration of the rock would be (1.63 , \text{m/s}^2) (calculated by dividing the change in velocity by the time taken).
What is the acceleration of a ball that starts from rest and rolls down a ramp and gains speed at 25 ms in 5 seconds?
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
A skydiver slows down from 54 ms to 5 ms by opening his parachute. If this takes .75 seconds what is the magnitude of the skydiver's acceleration?
The change in velocity is 54 m/s - 5 m/s = 49 m/s. The time is 0.75 seconds. Using the equation a = (vf - vi) / t, the acceleration is (49 m/s) / (0.75 s) = 65.33 m/s^2.
Janeequa can accelerate from standing still to running 11 miles per second in 5 seconds What is her acceleration?
apex :) 2.2 m/s2
A car is initially traveling at 20 ms when it accelerates to 35 ms in a time of 5 seconds?
The acceleration of the car is 3 m/s^2. This is calculated by taking the change in velocity (35 m/s - 20 m/s = 15 m/s) and dividing it by the time it took for the change in velocity to occur (5 seconds).
