The average rate of acceleration is (11/5) = 2.2 m/sec2 .
80 m/s2 up
The average acceleration during any interval is (change in speed) divided by (time for the change).A = (25 - 10)/5 = 15/5 = 3 meters per second2
80 m/s 2 up
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
The average rate of acceleration is (11/5) = 2.2 m/sec2 .
80 m/s2 up
The average acceleration during any interval is (change in speed) divided by (time for the change).A = (25 - 10)/5 = 15/5 = 3 meters per second2
80 m/s 2 up
The runner's acceleration can be calculated using the formula a = Δv/t, where Δv is the change in velocity (11 m/s - 0 m/s = 11 m/s) and t is the time taken (5 seconds). Therefore, the acceleration is 11 m/s divided by 5 seconds, which equals 2.2 m/s².
The acceleration of the rock can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values, we get acceleration = (8.15 m/s - 0 m/s) / 5 s = 1.63 m/s^2.
The acceleration of the rock would be (1.63 , \text{m/s}^2) (calculated by dividing the change in velocity by the time taken).
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
The change in velocity is 54 m/s - 5 m/s = 49 m/s. The time is 0.75 seconds. Using the equation a = (vf - vi) / t, the acceleration is (49 m/s) / (0.75 s) = 65.33 m/s^2.
apex :) 2.2 m/s2
The acceleration of the car is 3 m/s^2. This is calculated by taking the change in velocity (35 m/s - 20 m/s = 15 m/s) and dividing it by the time it took for the change in velocity to occur (5 seconds).
The acceleration can be calculated using the formula acceleration = (final velocity - initial velocity) / time. Substituting the values, we get acceleration = (5.5 m/s - 13 m/s) / 5 s = -1.5 m/s^2. The negative sign indicates deceleration.