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25q + 10d + 5n = 325 d = 5 + q, n = 2d = 10 + 2q so 25q + 10(5 + q) + 5(10 + 2q) = 325 ie 25q + 50 + 10q + 50 +10q = 325 1e 45q = 225 ie q = 5, so d = 10 and n = 20 Check (5 x 25) + (10 x 10) + (20 x 5) = 125 + 100 + 100 = 325 QED

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Q: Sally has 3.25 in change she has five more dimes then quarters but twice as many nickels as dimes give the answer as an algebraic equation and simplify each side of the equation?
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Provided you have quarters and nickels together equaling 5.30 dollars in which there are 8 more quarters than nickels how many nickels and quarters are there?

19 Quarters & 11 Nickels Let X = number of quarters & Y = number of nickels So, X = Y +8 (8 more quarters than nickels) 0.25*X + 0.05*Y = 5.30 Substitute first equation for x into second equation: 0.25*(Y+8) + 0.05*Y = 5.30 0.25Y + 2 + 0.05Y = 5.30 0.30Y + 2 = 5.30 0.30Y = 3.3 Y = 11 nickels, so the number of quarters X = 19 We can check these values with the second equation: 0.25*19 + 0.05*11 4.75 + 0.55 = 5.30


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