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I'll try to explain it.

We know that an adult's ticket is two times the cost of a child's ticket. We will call the child's ticket "y". If we do so, the adult's ticket will be 2"y" because it's two times the cost of a child's ticket. We also know that the total cost is 28. Now, we'll write an equation, knowing the number of children and adults and the relationship between the costs:

2*2y will be the two adult's tickets.

3*y will be the three children's tickets.

The equation:

2*2y+3*y=28

4y+3y=28

7y=28

y=4

Now, we know that ONE child's ticket costs 4. To find out how much an adult's ticket costs, we have to double it (look at the exercise, it says that an adult's ticket is two times the cost of a child's ticket).

4*2=8

Finally, we've found out that a child's ticket costs 4 and an adult's ticket costs 8.

We can check it as well:

2*8+3*4=16+12=28

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13y ago
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6mo ago

Let's assume the cost of a child's ticket is x. Then, the cost of an adult's ticket would be 2x. The total cost of two adults' tickets and three children's tickets is 2(2x) + 3(x) = 4x + 3x = 7x. We know that 7x = 28, so x = 4. Therefore, the cost of a child's ticket is $4, and the cost of an adult's ticket is $8.

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Q: Sam took his family to the zoo an adults ticket is two times the cost of a child's ticket the total cost for two adults tickets and three childrens tickets was 28 how much do the tickets cost?
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