10 coins would be tails up.
The conditional probability is 1/4.
If both tosses are fair, the probability of that outcome is one in four.
With 5 coin tosses there are 32 possible outcomes. 10 of these have exactly 2 heads, and 26 of these have 2 or more heads.For exactly two coins are heads: 10/32 = 31.25%For two or more heads: 26/32 = 81.25%
The probability is 0, since there will be some 3-tosses in which you get 0, 1 or 3 heads. So not all 3-tosses will give 2 heads.
The probability that a coin will land on heads - at least once - in six tosses is 0.9844
The conditional probability is 1/4.
If both tosses are fair, the probability of that outcome is one in four.
With 5 coin tosses there are 32 possible outcomes. 10 of these have exactly 2 heads, and 26 of these have 2 or more heads.For exactly two coins are heads: 10/32 = 31.25%For two or more heads: 26/32 = 81.25%
The probability is 0, since there will be some 3-tosses in which you get 0, 1 or 3 heads. So not all 3-tosses will give 2 heads.
The probability that a coin will land on heads - at least once - in six tosses is 0.9844
Heads+Heads ; Heads+Tails ; Tails+Tails
The probability of tossing heads on all of the first six tosses of a fair coin is 0.56, or 0.015625. The probability of tossing heads on at least one of the first six tosses of a fair coin is 1 - 0.56, or 0.984375.
The theoretical frequency of heads will be .5 and as you do more and more coin tosses the observed frequency should get closer and closer to .5. With 100 tosses, it will be pretty close, but not exactly .5
A total of 45 are heads. and a total of 45 are tails
Coin tosses are independent events. The probability of a head remains 1/2
The probability would be once in 128 attempts. You don't have to toss seven coins simultaneously. the 7 tosses just have to be independent of one another.
Pr(At least one head in three tosses) = 1 - Pr(No heads in three tosses) = 1 - Pr(Three tails in three tosses) = 1 - (1/2)*(1/2)*(1/2) = 1 - 1/8 = 7/8 or 0.875 or 87.5%