No.
5Y - X = 11 ( the 1 coefficient is always implied, not written )5Y = X + 11Y = (1/5)X + 11/5m(slope) = 1/5===========
A 1 in 14 slope is where when the height raises 1 inch from the slope it is equal to the road 14 inches up the hill.
For any two perpendicular lines (save a vertical and a horizontal one), the product of their slopes is always -1. For two perpendicular lines with one having a slope of -2, the other will have a slope equal to -1 divided by -2, which equals 1/2.
When the lines are horizontal and vertical. (slope of zero) (undefined slope)
The y-intercept is 0 and the slope is 1.
The slope is always positive A negative slope will always pass through quadrant II and IV
Slope is equal to rise over run. There are 12 inches in a foot, so 10 feet is actually 120 inches. Therefore, the slope is equal to 1/120.
The slope of two lines are perpendicular only if their slopes multiplied together equal -1 (m1*m2 = -1). So if a line has a slope of -3 then a line perpendicular to this one has a slope of -1/-3 or 1/3.
0
If the lines are in the form y = mx + c, the m values multiplied together should equal -1.Otherwise, the dot product of the two slope vectors should equal 0.
No, a positive slope is not always steeper than a negative slope. The steepness of a slope is determined by its absolute value, regardless of its sign. For example, a slope of +3 is steeper than a slope of -2, but a slope of +1 is less steep than a slope of -5. Thus, it depends on the specific values of the slopes being compared.
Perpendicular lines have slopes whose product is -1. As this is always true, if we think of .33 as about 1/3, then the perpendicular line would have a slope of -1/(1/3) which is -3.