Technically, in an ideal experiment, where there is lack of any opposing forces like air drag and friction, the period of oscillation of a pendulum only depends on the length of string (i.e, for r<<L). However, in presence of air drag, a force opposite to the velocity of the bob reduces the energy of oscillations, so it also
changes the period of oscillations.
acc to a law similar to stoke's law
Fv = -bv
where 'b' is a constant and depends on medium and the bob. So, the force acting on bob is the resultant of -w2x and -bv. this is how the period of oscillation depends on the velocity of pendulum bob.
The period of a simple pendulum of length 20cm took 120 seconds to complete 40 oscillation is 0.9.
Time period per oscillation=32/ 20=1.6 sec per oscillation.
The time period of a pendulum will increase when taken to the top of a mountain. This is because the acceleration due to gravity decreases at higher altitudes, resulting in a longer time for the pendulum to complete each oscillation.
The longer the pendulum is, the greater the period of each swing. If you increase the length four times, you will double the period. It is hard to notice, but the period of a pendulum does depend on the angle of oscillation. For small angles, the period is constant and depends only on the length of the pendulum. As the angle of oscillation (amplitude) is increased, additional factors of a Taylor approximation become important. (T=2*pi*sqrt(L/g)[1+theta^2/16+...] and the period increases. (see hyper physics: http://hyperphysics.phy-astr.gsu.edu/hbase/pendl.html) Interestingly, if the pendulum is supported by a very light wire then the mass of the object at the end of the pendulum does not affect the period. Obviously, the greater the mass, the less any air friction or friction at the pivot will slow the pendulum. Also interestingly, the pendulum period is dependant on the force of gravity on the object (g). One must not assume that g is constant for all places on Earth.
For a simple pendulum, consisting of a heavy mass suspended by a string with virtually no mass, and a small angle of oscillation, only the length of the pendulum and the force of gravity affect its period. t = 2*pi*sqrt(l/g) where t = time, l = length and g = acceleration due to gravity.
Mass oscillation time period = 2 pi sq rt. (m/k) Pendulum oscillation time period = 2 pi sq rt. (l/g)
T=1/f .5=1/f f=2
The period of a simple pendulum of length 20cm took 120 seconds to complete 40 oscillation is 0.9.
1. Length of the pendulum 2. acceleration due to gravity at that place
Time period per oscillation=32/ 20=1.6 sec per oscillation.
time taken by pendulum/to complete 1 oscillation
If you're thinking about a pendulum but not mentioning it, then no, it doesn't
Compound pendulum is a physical pendulum whereas a simple pendulum is ideal pendulum. The difference is that in simple pendulum centre of mass and centre of oscillation are at the same distance.
The weight of the bob will determine how long the pendulum swings before coming to rest in the absence of applied forces. The period, or time of 1 oscillation, is determined only by the length of the pendulum.
Same as it was in 1751, and same as it will be in 2051. Here is a link to an overview of pendulum calculations: http://en.wikipedia.org/wiki/Pendulum_(mathematics)
Yes, you can label it that way.
The physical parameters of a simple pendulum include (1) the length of the pendulum, (2) the mass of the pendulum bob, (3) the angular displacement through which the pendulum swings, and (4) the period of the pendulum (the time it takes for the pendulum to swing through one complete oscillation).