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Q: How many diagonals does a 50 sided polygon have?

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50*(50 - 3)/2 = 1175 diagonals.

48 because (50-2)*180 = sum of interior angles

what is a 50 sided polygon called?

The name of a 50 sided polygon is Pentacontagon.

50...

47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.

The name of a 50 sided polygon is Pentacontagon.

13agon and 50agon

It works out that a polygon with 1175 diagonals has 50 sides

The interior angle of a regular polygon with x sides is 180(x-2)/x. As a result, each angle of a regular 50-sided polygon is 172.8.

By looking at other polygons with less sides, we can see how many triangles they can fit. In a 4-sided polygon (square), you can fit 2 triangles. In a 5-sided polygon (pentagon), you can fit 3 triangles. In a 6-sided polygon (hexagon), you can fit 4 triangles. In an 8-sided polygon (octagon), you can fit 6 triangles. The pattern here is the number of triangles is equal to the number of sides minus 2. T = N - 2 So... 50 - 2 = 48. 48 triangles can fit into a 50-sided polygon.

The interior angle of a regular polygon with x sides is 180(x-2)/x. As a result, each angle of a regular 50-sided polygon is 172.8. The exterior angles are 7.2

the name for a 50 sided shape is a Pentacontagon;] ! xo

360 degrees

50 * * * * * Or a number smaller than 50 - including zero.

I find the name "30-sided polygon", "40-sided polygon", etc. just fine.

It is: (50-2)*180 = 8640 degrees

''pentacontagon''

Since the 50-sided polygon is a regular polygon, then:The sum of 50 angles = (50 - 2)(180⁰) = 48(180⁰) = 8,640⁰Each angle measure = 8,640⁰/50 = 172.8⁰

A 50-sided polygon would be called a pentacontagon.

A cuboid, by definition, has exactly six faces. So a 50 sided cuboid would be called an impossibility. There are many configurations that can give rise to a solid object with 50 faces. For example: a pyramid shape with a 25-sided polygon as base or a prism with 48 sided polygons at each end. There are lots more possibilities and each would have a different name.

for any polygon with 'n' number of sides, the number of diagonals will be n(n-3) / 2 if n is 50, no. of diagonals will be 50(50-3)/2 = 47*25 = 1175 how do you get it? take any polygon, say septagon i.e. with 7 sides if you take 1 vertice, remainig vertices will be 7-1 that is 6. there will be 2 consecutive vertices for any vertice, so here, this one has 2 consecutive vertices(its always like that) so the remaining vertices is 6-2 that is 4. remember : a diagonal connects non consecutive vertices so you know that from one vertice, there will be 4 diagonals. multiply it by the total no. of vertices(here 7) 4*7 = 28 now divide this by 2 (since 2 vertices share the same diagonal) therefore, 28/2 = 14 which is the no. of diagonals in a septagon. so for an n-gon, the number of diagonals will be n(n-3) / 2 hope it helps! p.s. i figured it out myself during math class. then i tried it on many polygons.

50 since there are 100 vertices ("gons") and it takes two vertices to connect a diagonal, there will be 50 diagonals.

Commonly a polygon with more then 10 sides is referred to as n-gon for example one with 48 sides would be a 48gon.The closest actually named polygon to a 48gon is a Pentacontagon which has 50 sides.

8640 degrees The sum of the interior angles of an n-sided polygon is: 180(n-2). For n=50, we have 180(50-2)=180(48)=8640 degrees