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Sin2A plus sin2B plus sin2C 4sinAsinBsinC proove it?

Updated: 9/24/2023

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∙ 9y ago

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The proof that sin2A plus sin2B plus sin2c equals 4sinAsinBsinC lies in the fact that (sin 2A + sin 2B + sin 2C) = 4 sinA.sinB.sinC.

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