answersLogoWhite

0

Subjects>Math>Math & Arithmetic

Sin2A plus sin2B plus sin2C 4sinAsinBsinC proove it?

User Avatar

Anonymous

∙ 11y ago
Updated: 9/24/2023

The proof that sin2A plus sin2B plus sin2c equals 4sinAsinBsinC lies in the fact that (sin 2A + sin 2B + sin 2C) = 4 sinA.sinB.sinC.

User Avatar

Wiki User

∙ 11y ago
Copy

What else can I help you with?

Continue Learning about Math & Arithmetic
Related Questions
Trending Questions
What is 11 percent of 21percent? What is the Roman numeral for four? How do you write 3.9 million in digit form? What is 92.48 as a mixed number in simplest form? What is 50 rounded to the nearest 10? What numbers can go into 634? What is the natural logarithms in mathematics? What is a multiple of 60? What makes a pictogram more compelling than a bar chart? What is the conversion 80 feet per second into miles per hour? B P is the Queen's house? How much money does a spy make a year? Percent of female and male in LA? How do you write an numerical expression for 7 point 7 million? Divide x3 - 125 by x - 5? What words have vertical reflectional? How do you write -0.151515151515151515151515151515 as a fraction? Midpoint of 16 and 21? What does 1 cm transfer to in mm? Does the amplitude of a sine function describe the distance between the highest and lowest values of the function?

Resources

Leaderboard All Tags Unanswered

Top Categories

Algebra Chemistry Biology World History English Language Arts Psychology Computer Science Economics

Product

Community Guidelines Honor Code Flashcard Maker Study Guides Math Solver FAQ

Company

About Us Contact Us Terms of Service Privacy Policy Disclaimer Cookie Policy IP Issues
Answers Logo
Copyright ©2026 Infospace Holdings LLC, A System1 Company. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Answers.