It's 2.5
6•b-11
The number is 11
18
11 times 9 = 99. The way you figure this out is whenever you have a one-digit number times 11, that number becomes doubled. For example, 11 times 9= 99. See, the nine got doubled. Another example, 6 times 11= 66. The six got doubled so it is now 66.
You get the sum of 11 two ways; 5,6 and 6,5.
Let the number be represented as ( x ). The expression for the sum of 10 times the number and 15 added to 11 times the same number can be written as ( 10x + (11x + 15) ). Simplifying this gives ( 21x + 15 ). Therefore, the sum is ( 21x + 15 ).
11x6
To ensure that you get the same sum at least six times when throwing two dice, you can use the pigeonhole principle. There are 11 possible sums (from 2 to 12). If you throw the dice 55 times, then by the pigeonhole principle, at least one sum must occur at least six times, because (55 \div 11 = 5) remainder 0, meaning each sum can occur up to five times before hitting the sixth. Thus, you need to throw the dice 55 times to guarantee that the same sum appears at least six times.
11 5 more than six is the same as saying 5+6
Six times.
4
1/6 x 6/11 = 6/66 = 1/11