Six consecutive numbers that have the sum of 273?
Suppose the smallest number is x. Then the six numbers are
x, x+1, x+2, x+3, x+4 and x+5.
Their sum is 6x+15 which is 273. So 6x = 273-15 = 258
So x = 258/6 = 43.
The six numbers are 43, 44, 45, 46, 47 and 48.