theres 12 numbers evenly spaced on a clock , so you divide 360 by 12 and you get the angle in between each number
To find use the following equationobject size = distance x (smallest angle/57.3°)Since Arecibo is on Earth, to find the distance take the distance between the sun and Earth (in AU) and subtract the distance between the sun and Venus (in AU). Then multiply the AU by 1.5 x 108 (or the number of kilometers in 1 AU)1 AU - 0.72 AU = 0.28 AU0.28 AU x 1.5 x 108 = 4.2 x 107 kmFor 1'object size = 4.2 x 107 x (1/60°/57.3°)object size = 12216.4 kmFor 1"object size = 4.2 x 107 x (1/3600°/57.3°)object size = 203.6 km
Because it is. The earth rotates which makes the sun shine on different parts of the earth which has different times. These are called TIME ZONES. So in France, the sun shines at this particular time which makes the sun shine at another angle in Canada
Since central time is 2 hours ahead of Pacific time, 1 pm Pacific would be 3 pm central
Yes. The proportionality constant is ' 1 '.
The angle between the north star and your northern horizon is approximately the same as your latitude north of the equator.
30 degrees
It can be any size at all, between zero and 360 degrees.If the nonagon is regular, then the angle measures 140 degrees.
1
The number of memory between 12 and 1 is 5. There are 60 lines in a clock: 5/60. Since the whole angle of the clock is 360, you multiply 360 and 5/60 together and get the answer of 30 degrees.
at 11 oclock
1 oclock
An angle of 52 degrees, as with any angle between 1 and 89 degrees, is an acute angle.
in mod 12 which is the same as clock time... 6 oclock plus seven = 1 oclock
an acute angle measure from 1 degree to 89 degrees
One full revolution of the clockface equates to 3600. Then the angle between consecutive hours is 360/12 = 300. The angle between 1 and 4 = 3 hours is therefore 3 x 30 = 900. The obtuse angle is thus 360 - 90 = 2700.
If you know the gradient for a line (the m in y = mx + c) then tan-1 (m) will give you the angle between the line and the x axis. So do tan-1 for both gradients and subtract to find angle between the lines.
It is a fraction between 1/4 and 1/2.