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Slope of perpendicular line is the negative reciprocal. So it is -1/4

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Q: Slope of a line AB is 4 what is the slope of CD if CD is perpendicular to AB?
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If AB contains the points 6 -2 and -3 16 what is the slope of a line perpendicular to AB?

0.5


How do you work out an equation for the perpendicular bisector of the line segment AB when A is at -4 8 and B is at 0 -2?

First find the midpoint of the line segment AB which is: (-2, 3) Then find the slope of AB which is: -5/2 The slope of the perpendicular bisector is the positive reciprocal of -5/2 which is 2/5 Then by using the straight line formula of y-y1 = m(x-x1) form an equation for the perpendicular bisector which works out as:- y-3 = 2/5(x-(-2)) y = 2/5x+4/5+3 y = 2/5x+19/5 => 5y = 2x+19 So the equation for the perpendicular bisector can be expressed in the form of:- 2x-5y+19 = 0


If line ab contains points 4 19 and -3 5 what is the slope of a line perpenduiclar to lineab?

negative 1/2


How do you form an equation for the perpendicular bisector of the line AB when A is at the point of 7 3 and B is at the point of -6 1?

First find the midpoint of AB which is (1/2, 2) Then find the slope of AB which is 2/13 The slope of the perpendicular bisector is the negative reciprocal of 2/13 which is -13/2. Then by using the formula y-y1 = m(x-x1) form an equation for the perpendicular bisector which works out as:- y -2 = -13/2(x -1/2) y = -13/2x + 13/4 + 2 y = -13/2x + 21/4 So the equation is: 4y = -26x + 21


Two points to point slope form?

Let : A ≡ ( x1, y1 ) ≡ ( 4, - 4), B ≡ ( x2, y2 ) ≡ ( 9, -1 ).Then, slope of line AB ism = ( y₂ - y₁ ) / ( x₂ - x₁ ) = (-1 + 4 ) / ( 9 - 4 ) = 3/5Hence, equation of line AB in Point-Slope Form isy - y₁ = m ( x - x₁ )y + 4 = (3/5) ( x - 4 ) .................... (1)5y + 20 = 3x - 125y = 3x - 32y = (3/5)x + (-32/5) ....................... (2)This is the Slope-Intercept Formy = mx + b.The form which is easier to get isSlope-Point Form. But this is one'spersonal choice.

Related questions

Suppose the slope of AB is zero what is the slope of CD given that a. CD is parallel to AB b. CD is perpendicular to AB?

Any line that is parallel to another line will have the same slope. So if line AB's slope is zero and line CD is parallel to AB, then its slope will also be zero. The slope of line CD, when perpendicular to AB, will be infinity. If line AB has a slope of zero that means its just a horizontal line passing some point on the y-axis. A line that is perpendicualr to this one will pass through some point on the x-axis and therefore have an infinite slope.


If AB contains the points 6 -2 and -3 16 what is the slope of a line perpendicular to AB?

0.5


If line AB contains the points 4 19 and -3 5 what is the slope of a line perpendicular to AB?

-1/2 or -0.50


The slope of line ab is 3 what is the slope of line CD if CD is parallel to ab?

3


If AB is parallel to CD and the slope of CD is one over two what is the slope of AB?

The slope of line AB will be 1/2. Two parallel lines will always have the same slope, so if you know the slope of one line that is parallel to another, you know the other line's slope.


If AB is parallel to CD and the slope of CD is -8 what is the slope of AB?

If the lines AB and CD are parallel then they both will have the same slope of -8 but with different y intercepts


Find slope of the line ab?

If point a has coordinates (x1,y1), and point b has coordinates (x2, y2), then the slope of the line is given by the formula: m = (y2-y1)/(x2-x1).


What is a perpendicular bisector of a line segment?

The perpendicular bisector of a line segment AB is the straight line perpendicular to AB through the midpoint of AB.


Which of these lines has a slope of 2?

AB


How do you work out an equation for the perpendicular bisector of the line segment AB when A is at -4 8 and B is at 0 -2?

First find the midpoint of the line segment AB which is: (-2, 3) Then find the slope of AB which is: -5/2 The slope of the perpendicular bisector is the positive reciprocal of -5/2 which is 2/5 Then by using the straight line formula of y-y1 = m(x-x1) form an equation for the perpendicular bisector which works out as:- y-3 = 2/5(x-(-2)) y = 2/5x+4/5+3 y = 2/5x+19/5 => 5y = 2x+19 So the equation for the perpendicular bisector can be expressed in the form of:- 2x-5y+19 = 0


If line ab contains points 4 19 and -3 5 what is the slope of a line perpenduiclar to lineab?

negative 1/2


How do you form an equation for the perpendicular bisector of the line AB when A is at the point of 7 3 and B is at the point of -6 1?

First find the midpoint of AB which is (1/2, 2) Then find the slope of AB which is 2/13 The slope of the perpendicular bisector is the negative reciprocal of 2/13 which is -13/2. Then by using the formula y-y1 = m(x-x1) form an equation for the perpendicular bisector which works out as:- y -2 = -13/2(x -1/2) y = -13/2x + 13/4 + 2 y = -13/2x + 21/4 So the equation is: 4y = -26x + 21