Slope of perpendicular line is the negative reciprocal. So it is -1/4
0.5
First find the midpoint of the line segment AB which is: (-2, 3) Then find the slope of AB which is: -5/2 The slope of the perpendicular bisector is the positive reciprocal of -5/2 which is 2/5 Then by using the straight line formula of y-y1 = m(x-x1) form an equation for the perpendicular bisector which works out as:- y-3 = 2/5(x-(-2)) y = 2/5x+4/5+3 y = 2/5x+19/5 => 5y = 2x+19 So the equation for the perpendicular bisector can be expressed in the form of:- 2x-5y+19 = 0
negative 1/2
First find the midpoint of AB which is (1/2, 2) Then find the slope of AB which is 2/13 The slope of the perpendicular bisector is the negative reciprocal of 2/13 which is -13/2. Then by using the formula y-y1 = m(x-x1) form an equation for the perpendicular bisector which works out as:- y -2 = -13/2(x -1/2) y = -13/2x + 13/4 + 2 y = -13/2x + 21/4 So the equation is: 4y = -26x + 21
Let : A ≡ ( x1, y1 ) ≡ ( 4, - 4), B ≡ ( x2, y2 ) ≡ ( 9, -1 ).Then, slope of line AB ism = ( y₂ - y₁ ) / ( x₂ - x₁ ) = (-1 + 4 ) / ( 9 - 4 ) = 3/5Hence, equation of line AB in Point-Slope Form isy - y₁ = m ( x - x₁ )y + 4 = (3/5) ( x - 4 ) .................... (1)5y + 20 = 3x - 125y = 3x - 32y = (3/5)x + (-32/5) ....................... (2)This is the Slope-Intercept Formy = mx + b.The form which is easier to get isSlope-Point Form. But this is one'spersonal choice.
Any line that is parallel to another line will have the same slope. So if line AB's slope is zero and line CD is parallel to AB, then its slope will also be zero. The slope of line CD, when perpendicular to AB, will be infinity. If line AB has a slope of zero that means its just a horizontal line passing some point on the y-axis. A line that is perpendicualr to this one will pass through some point on the x-axis and therefore have an infinite slope.
0.5
-1/2 or -0.50
3
The slope of line AB will be 1/2. Two parallel lines will always have the same slope, so if you know the slope of one line that is parallel to another, you know the other line's slope.
If the lines AB and CD are parallel then they both will have the same slope of -8 but with different y intercepts
If point a has coordinates (x1,y1), and point b has coordinates (x2, y2), then the slope of the line is given by the formula: m = (y2-y1)/(x2-x1).
The perpendicular bisector of a line segment AB is the straight line perpendicular to AB through the midpoint of AB.
AB
First find the midpoint of the line segment AB which is: (-2, 3) Then find the slope of AB which is: -5/2 The slope of the perpendicular bisector is the positive reciprocal of -5/2 which is 2/5 Then by using the straight line formula of y-y1 = m(x-x1) form an equation for the perpendicular bisector which works out as:- y-3 = 2/5(x-(-2)) y = 2/5x+4/5+3 y = 2/5x+19/5 => 5y = 2x+19 So the equation for the perpendicular bisector can be expressed in the form of:- 2x-5y+19 = 0
negative 1/2
First find the midpoint of AB which is (1/2, 2) Then find the slope of AB which is 2/13 The slope of the perpendicular bisector is the negative reciprocal of 2/13 which is -13/2. Then by using the formula y-y1 = m(x-x1) form an equation for the perpendicular bisector which works out as:- y -2 = -13/2(x -1/2) y = -13/2x + 13/4 + 2 y = -13/2x + 21/4 So the equation is: 4y = -26x + 21