Area of circle=(pi) r2=7.70 sq m
r2=2.45
r=1.565
Perimeter of circle=2(pi)r
=2*3.14*1.565
=9.82
Cost of Fencing it at Rs.3.5 per meter = 9.82*3.5
=34.39(nearly)
2*pi*radius or pi*diameter
A circle, radius 56/2 pi = 28/pi = 8 feet 11 inches which would have an area of 249¾ squinches
Yes, it is.
Area of a circle = pi*radius2
When graphing inequalities you use a circle to indicate a value on a graph. If the value is included in the solution to the inequality you would fill in the circle. If the value that the circle represents is not included in the solution you would leave the circle unshaded.
176 m of fencing. Area of circle = 2*pi*radius
The solution set is all points on the circle.
2*pi*radius or pi*diameter
If the shape of the area is a square, it would take 1,181 feet of fencing for the perimeter. If the area is a circle, you will need 1,046 feet of fencing.
A circle, radius 56/2 pi = 28/pi = 8 feet 11 inches which would have an area of 249¾ squinches
open circle menas it is not part of the solution set and closed circle means that it is part of the solution
Yes, it is.
Area of a circle = pi*radius2
u make your working model of area of circle with your use of brain
When the number represented by that circle is part of the solution.
It is an "open" circle. That is, a circle which is not filled in.
When graphing inequalities you use a circle to indicate a value on a graph. If the value is included in the solution to the inequality you would fill in the circle. If the value that the circle represents is not included in the solution you would leave the circle unshaded.