The only way this could be true is under one of the following conditions:
Consider:
ab = c
bc = a
First, plug the second equation into the first one to find the value of b:
(bc)(b) = c
b2c = c
b2 = 1
b = ±1
Now take those values and plug it into either equation:
(1)(c) = a
c = a
or:
(-1)(c) = a
c = -a
To prove that the absolute values of c and a must be identical:
Given:
ab = c
bc = a
Then:
ab/c = 1
bc/a = 1
Therefore:
ab/c = bc/a
a2b = bc2
a2 = c2
|a| = |c|
The Associative property of multiplication states that the product of a set of three numbers is always the same no matter which operation is carried out first.For example Ax(BxC) = (AxB)xC and so either can be written as AxBxC.ie 3x(4x5) = 3x20 = 60and (3x4)x5 = 12x5 = 60It is important not to confuse this with the commutative (or Abelian) property which states that the order of the numbers does not matter. ie AxB = BxAMatrix multiplication, for example, is associative but NOT commutative.(a * b) * c = a * (b * c)As a result, we can write a * b * c without ambiguity.
axb + cxd
The answer depends on where the points A, B, C and X are. And since you have not bothered to provide that information, I cannot provide a sensible answer.
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
Particular integral is finding what the integral is for example the integral of 2x is x^2 + C. Finding the particular solution would be finding what C equals from the particular integral.
AxB=BxA (AxB)xC=Ax(BxC) Ax(B+C)=AxB+AxC Ax1=A Ax0=0
It equals b times c.
You can definitely multiply 2x2 matrices with each other. In fact you can multiply a AxB matrix with a BxC matrix, where A, B, and C are natural numbers. That is, the number of columns of the first matrix must equal the number of rows of the second matrix--we call this "inner dimensions must match."
The Associative property of multiplication states that the product of a set of three numbers is always the same no matter which operation is carried out first.For example Ax(BxC) = (AxB)xC and so either can be written as AxBxC.ie 3x(4x5) = 3x20 = 60and (3x4)x5 = 12x5 = 60It is important not to confuse this with the commutative (or Abelian) property which states that the order of the numbers does not matter. ie AxB = BxAMatrix multiplication, for example, is associative but NOT commutative.(a * b) * c = a * (b * c)As a result, we can write a * b * c without ambiguity.
bc or b*c or b.c or bxc depending on the notation being used.
if x = multiplication. its as written, which would be abc ex. 3x4x5 = (3)(4)(5) = 60 if x= cross production, then you cross axb first, then bross (axb) x c where (axb) is wut u got by crossing axb. This is if u have no brackets. its just axbxc
axb + cxd
4.800000000000001
its 7!
The value of c is 6
-15+c+5 = 75 c = 75+15-5 c = 85
f = B x C