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This is an expression, not an equation or inequality and so cannot be solved.

b2 + b - 20 can be factorised into (b - 4)(b + 5)

Q: Solve b squared plus b minus 20?

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4x + 20

x2+x-380 = (x+20)(x-19) when factored

The solutions are: x = 4, y = 2 and x = -4, y = -2

36. 4 squared is 16...16 + 20 - = 36.

-5 + (-4) - 12 - 20 - (-10) + 6 = -25

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4x + 20

x - 2

Factor out -2: -2(x squared +11x-20). This is fully factored.

answer is p/5. problem: {[(p^2)-3p]/[(p^2)-6p+9]}/{20/(4p-12)}

x2+x-380 = (x+20)(x-19) when factored

-20 negative 20 minus 20

x2 - 9x + 20 = (x - 4)( x - 5)

(x - 5)(x + 4)

3x^2=-20 so x^2=-20/3 this has no real roots but the plus of minus i(square root of 20/3) is a solution if we allow complex numbers.

62 - 16 = 20

The solutions are: x = 4, y = 2 and x = -4, y = -2

36. 4 squared is 16...16 + 20 - = 36.