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Q: What are the solutions to the simultaneous equations of x squared plus y squared equals 20 and 2y minus x equals 0?

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They are: (3, 1) and (-11/5, -8/5)

These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.

1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)

They are simultaneous equations and their solutions are x = 41 and y = -58

Merge the equations together and form a quadratic equation in terms of x:- 3x2-20x+28 = 0 (3x-14)(x-2) = 0 x = 14/3 or x = 2 So when x = 14/3 then y = -13/3 and when x = 2 then y = 1

Related questions

They are: (3, 1) and (-11/5, -8/5)

If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)

The two rational solutions are (0,0,0) and (1,1,1). There are no other real solutions.

These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.

1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)

Through a process of elimination and substitution the solutions are s = 8 and x = 5

They are simultaneous equations and their solutions are x = 41 and y = -58

Simultaneous suggests at least two equations.

Do you mean: 4x+7y = 47 and 5x-4y = -5 Then the solutions to the simultaneous equations are: x = 3 and y = 5

Merge the equations together and form a quadratic equation in terms of x:- 3x2-20x+28 = 0 (3x-14)(x-2) = 0 x = 14/3 or x = 2 So when x = 14/3 then y = -13/3 and when x = 2 then y = 1

Simultaneous equations.

The system is simultaneous linear equations

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