3x + y + 1 = 0
y = - 3x - 1
2x - 3y + 8 = 0
3y - 2x - 8 = 0
3y = 2x + 8
y = 2x/3 + 8/3
-3x - 1 = 2x/3 + 8/3
-9x - 3 = 2x + 8
-11x = 11
x = -1
y = -3x - 1 = 3 - 1 = 2
The graphs intersect at the point (-1, 2).
The roots of the quadratic equation are the x-intercepts of the curve.
3x + 4y = 5x - 2y = 5leads to:x = 5 + 2ySo:3(5 + 2y) + 4y = 515 + 10y = 510y= -10y=-1and therefore if y = -1 then x = 3.
There are infinitely many "solutions". In the Cartesian plane, the coordinates of any point on the line defined by y = x + 2 is a solution. Thus, any ordered pair, (x, x+2) is a solution.
If by sperical triangle you mean a triangle on the surface of a sphere, you will need 3 dimensional coordinate geometry. Whether you use polar coordinates or linear coordinates will depend on what you want to "solve".
True
Plot the straight line representing 2y = 12 - x. Plot the straight line representing 3y = x - 2 The coordinates of the point of intersection of these two lines is the solution to the simultaneous equations.
Solve the two equations simultaneously. The solution will be the coordinates of the point of intersection.
Graphically might be the simplest answer.
x-2y=8 3x-6y=6
The first graph consists of all points whose coordinates satisfy the first equation.The second graph consists of all points whose coordinates satisfy the second equation.The point of intersection lies on both lines so the coordinates of that poin must satisfy both equations.
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The roots of the quadratic equation are the x-intercepts of the curve.
For example, the equation of a line: y = ax + b. the equation of a curve: y = cx2 + dx + e ax + b = cx2 + dx + e (solve for x)
3x + 4y = 5x - 2y = 5leads to:x = 5 + 2ySo:3(5 + 2y) + 4y = 515 + 10y = 510y= -10y=-1and therefore if y = -1 then x = 3.
The incenter is the intersection of the interior angle bisectors.
Finding the point of intersection using graphs or geometry is the same as finding the algebraic solutions to the corresponding simultaneous equations.
There are infinitely many "solutions". In the Cartesian plane, the coordinates of any point on the line defined by y = x + 2 is a solution. Thus, any ordered pair, (x, x+2) is a solution.