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3x + y + 1 = 0
y = - 3x - 1

2x - 3y + 8 = 0
3y - 2x - 8 = 0
3y = 2x + 8
y = 2x/3 + 8/3


-3x - 1 = 2x/3 + 8/3
-9x - 3 = 2x + 8
-11x = 11
x = -1
y = -3x - 1 = 3 - 1 = 2

The graphs intersect at the point (-1, 2).

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Q: Solve graphically 3x plus y plus 1 equals 0 and 2x - 3y plus 8 equals 0 Write down the co-ordinates of the point of intersection of the two lines?
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