Add 4x + 2x = 6x + 4 = 6x + 4
x = 4 and y = 0
3x+4 = 2x-3 3x-2x = -3-4 x = -7
There is no solution to: 4(2x + 2) + 12 > 1004(2x + 2) + 12 > 100 For 4(2x + 2) + 12 > 1004(2x + 2) + 12 to have a solution x < -1 which makes 1004(2x + 2) + 12 < 12, BUT 1004(2x + 2) + 12 is supposed to be greater than 100. Perhaps there is a missing operator in the digits of 1004?
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)
3x - 2 = 2x + 4 3x - 2x = 4 + 2 x = 6
2x + 4 = 16 2x = 16 - 4 2x = 12 x = 12/2 x = 6
2x+3 = 7 2x = 7-3 2x = 4 x = 2
(2x+3)(2x+4)
When using substitution the answer to y0.5x plus 2 -y-2x plus 4 is y = -2 (x-1.
3x + 2x = 5x. 5x= (-4) X = (-4)/5 x= -0.8
1 + 3x - x = x - 4 + 2x 1 + 4 = x + 2x - 3x + x 5 = x