The inequality sign got lost when writing the question. Anyway, inequalities are basically solved the same way as equations; you transfer everything that has the variable ("x") to one side, and everything else to the other side of the equation - or inequality. The major care you must take is that in an inequality, if you multiply or divide by a negative number, the inequality sign changes direction - for example, a less-than becomes a greater-than.
so = -4y < -20 making y < 5
p>9
There appears to be no inequality in the question: only some disjoint expressions. Expressions cannot be solved.
It is 5,000,000 or 5 million.
3x + 2x < 6 Add the terms on the left side: 5x < 6 One can perform the same operation to both sides of the inequality. If one divides by a positive number then the inequality retains it 'sense'. In this case, it remains a '<'. Divide both sides by 5: 5x / 5 < 6 / 5 x < 6 / 5 ( the answer )
so = -4y < -20 making y < 5
p>9
You cannot solve it because it is an expression - not an equation nor inequality.
It is an algebraic expression. An inequality includes '>' or '
There appears to be no inequality in the question: only some disjoint expressions. Expressions cannot be solved.
It is 5,000,000 or 5 million.
3x + 2x < 6 Add the terms on the left side: 5x < 6 One can perform the same operation to both sides of the inequality. If one divides by a positive number then the inequality retains it 'sense'. In this case, it remains a '<'. Divide both sides by 5: 5x / 5 < 6 / 5 x < 6 / 5 ( the answer )
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
-7x + 6 + 7x - 2 = 4
a= -0.8
Q=CV, with Q=(5x10) = 50 Coulombs, and C=5x10^-6 Farads, therefore: 50 = 5x10^-6 x V V = 50 / (5x10^-6) = 10,000,000 Volts. Seems like rather a lot! Maybe there's a typo in the question? Either way, use Q=CV to give the right answer. is this right seems rather high to (50 volts?)
There cannot be an answer since there is no equation or inequality. The expression can be simplified to -6f -6 or -6(f + 1)