3x + 2x < 6 Add the terms on the left side: 5x < 6
One can perform the same operation to both sides of the inequality. If one divides by a positive number then the inequality retains it 'sense'. In this case, it remains a '<'.
Divide both sides by 5: 5x / 5 < 6 / 5
x < 6 / 5 ( the answer )
-2x + 6 <= 4x + 18 -2x <= 4x + 12 -12 <= 6x -2 <= x
2x + 5 - 5 = 2x. You can not solve for x because this is not an equation.
this can not be solved un less with another equation
2x+a=p 2x=p-a x=.5p-.5a
2x + 3 is an expression that is already in simplest form; you cannot "solve" it.
It can't be solved because the discriminant of this quadratic equation is less than zero
-2x + 6 <= 4x + 18 -2x <= 4x + 12 -12 <= 6x -2 <= x
2x + 5 - 5 = 2x. You can not solve for x because this is not an equation.
this can not be solved un less with another equation
2x+a=p 2x=p-a x=.5p-.5a
2x + 3 is an expression that is already in simplest form; you cannot "solve" it.
The two inequalities define a region of the coordinate plane: there is no unique solution.
To solve for x, set up the equation: 2x +2x = 40 (then simplify) 4x = 40 (then divide both sides of the equation by 4) x = 10 (this is the answer)
5x+8x+3x-2x = 14x
The solution to the equation 2x plus 2 is 2(x + 1).
y= -2x
2x + 9x simplified would be 11x