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Starcoke724 ∙
2*(10^y + 11) = 4 - 5*(1 - 10^y)
2*10^y + 22 = 4 - 5 + 5*10^y
23 = 5*10^y - 2*10^y = 3*10^y
Therefore 10^y = 23/3
and so y = log(23/3) = 0.885
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