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Q: Solve the following inequality 38 4x3 plus 7-3x?

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4x3=12

(4x3)+2 = 14

4x3+12x2+3x+9

12x

4x3+10x2+2x+5= (2x+5)(2x2+1)

4x3=12 250-12=238 238/50=4.76

14

no

4x(x + 11)(x + 5)

4x3 times 4x3 = 16x6

2x(2x2 - 9x + 5)

It is usually referred to as an equation.

The "degree" is the highest power - in this case, the 3 in 4x3 (4 times to the third power).

it could be anything. What is a? if it is 3 then you do 4x3=12+3x3=9+3=24 * * * * * It is 8a.

x4 - 4x3 - 12x2 -32x + 64 (x - 4)(x + 2)(x + 2)(x - 4)

4x3+6x7 = (4x3)+(6x7) = 12+42 = 54 in the rules of calculation the times has to be done before the plus so the 6x7 must be figured out before you can add.

12x6 - 16x3 - 15x3 + 20 = 4x3(3x3 - 4) - 5(3x3 - 4) = (3x3 - 4)(4x3 - 5)

21-4x3 is equal to 9.

4x3 + 16x2 - 180x = 4x(x2 + 4x - 45) = 4x(x + 9)(x - 5)

Yes, 4x3 or 3x4 does equal 12.

Yes. Before using the polynomial for any productive purpose, it would have to be cleaned up and simplified. In that process, the +3x4 and -3x4 would go away, and the highest-order term remaining would be the 4x3.

12/3+4x3=4+12=16

4x3 + 2x2 - 6 has three terms.

log4+log3=log(4x3)=log12

When x = 2, 4x3 = 32