2y = 4x + 4y = 2x + 2
x = -1.2, y = -3
you can not solve this equation
Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
2y + 4 = 3ySubtract 2y from both sides:4 = ywhew
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
Subtract by 7x and divide by 2.
3x+2y=6 2y=-3x+6 y=-1.5x+3
6x+2y=4 gives y=2-(1/3)x
x = 3 and y = 3 Form a simultaneous equation and solve by elimination.
3y + 2y + 4 + 1 = 805y + 5 = 805y = 75y = 15
You cannot solve one linear equation in two unknown variables.
3x + 2y = 62x + 3y = -1You can use substition, elimation, or graphing to solve this system, but I prefer to use matrices. They are difficult to type out, but the answer is x = 4 and y = -3.
By elimination: x = 3 and y = 0
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
X+2y=6 how to solve? 2y=6-x then y=3-x so y=3-x
80 = 3y + 2y + 4 + 1 75 = 5y 15 = y y = 15
y=16 x= -4
2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.
Add them: 4x = 4 so x = 1 and y must be 4
-2y = 10 2y = -10 y = -5
4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
x + 52 + 2y + 35 = 3 x + 2y = 3 - 52 -35 x + 2y = -84 Infinite number of solutions, are you sure you posted the correct equation?