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It is not possible to do so because the question contains one equation (5x + y = 1) and one expression (3x + 2y + 2). An expression cannot be solved.

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Algebra

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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: Solve this equation using substitution 5x plus y equals 1 and 3x plus 2y plus 2?
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You cant solve it unless it is an equation. To be an equation it must have an equals sign.


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Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".


How would use solve the system of equation x plus 3y equals 23 by using substitution?

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Solve this system of equation using substitution 2x plus 6y equals 24 and 3x-2x equals 24 ?Improved Answer:2x+6y = 243x-2x = 24 => x =24Substitute the value of x into the top equation to find the value of y:48+6y = 246y = 24-486y = -24y = -4So: x = 24 and y = -4


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Mathematical substitution is the process of using one equation to solve for multiple variables. For example: Equation 1: x + y = 4 Equation 2: 2x + y = 16 Using equation 1, solve for y: y = 4 - x <-- Plug this into equation 2. This is substitution because you are replacing y in equation 2 with what y is equal to in equation 1. 2x + y = 16 ----> 2x + (4 - x) = 16 Now you can solve for x: x + 4 = 16; x = 12 You can then substitute the value of x back into the equation that is solved for y: y = 4 - 12; y = -8 Check both equations: Equation 1: -8 + 12 = 4; 4 = 4 (Correct) Equation 2: 2(12) + (-8) = 16; 24 - 8 = 16; 16 = 16 (Correct) We have successfully used substitution to solve for two different variables, x and y.


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To solve a system of equations using substitution you solve one of the equations for one of the variables then substitute that into the other equation to solve for the other variable. For example. y = 6x 2x + 3y = -20 The first equation has already been solved for y. So, you simply substitute that into the second equation. 2x + 3(6x) = -20 2x + 18x = -20 20x = -20 x = -20/20 = -1 Now you have solved for x. You can substitute your answer for x back into the first equation to solve for y. y = 6x = 6(-1) = -6 Putting it all together... x = -1 y = -6


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What is the disadvantage of using the substitution method in solving linear equations rather than the graph method?

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Solve the following equation using the quadratic formula. -5X2 equals -7X plus 6?

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Solve this equation using addition method -8x plus 3y equals -5 and 8x subtract 2y equals 6?

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