To solve this system of equations using substitution, we can isolate one variable in one equation and substitute it into the other equation. From the second equation, we can express x in terms of y as x = 4 + 2y. Then, substitute this expression for x into the first equation: 4(4 + 2y) - 3y = 1. Simplify this equation to solve for y. Once you find the value of y, substitute it back into x = 4 + 2y to find the corresponding value of x.
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If: x+y = 4 and y = 2x+1 Then: 4-x = 2x+1 => 3 = 3x => 1 = x So by substitution: x = 1 and y = 3
x = -2 and y = 1
-2
x2 + y2 = 1x2- x2+ y2= 1 - x2y2 = 1 - x2y =± √(1 - x2)
In that instance, it means that the lines never touch.