Q: Square root of 25 is integer?

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Square root of 25 = 251/2 = 5, which is an integer. So the square root of 25 is integer.

The opposite of the integer of -25

The symbol is not considered an integer. Thevalue of the square root is, though.

The square root of 25 is 5, which is a whole number, an integer, a natural number and a rational number.

The square root of an integer is a CYCLOTOMIC integer.

√479 ≈ 21.89 √500 ≈ 22.36 Making 22 as the integer between them.

no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...

Negative 64 is the square root of an integer. The square root of -64 is not an integer.

The square root of 3 is not an integer.

Is the square root of a 100 is a integer

No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106

No, the square root of an integer will not always be an integer. It may or may not be. The square root of nine is three, both of which are integers. The square root of two is not an integer. In fact, it is not even a rational number.

Yes, e.g. sqrt(25)=5

-- If the square root is an integer, then add ' 1 ' to it. -- If the square root is not an integer, then there isn't any.

The square root of 36 is 6 which is an integer.

A number such as 4, 25, 16, whose square root is an integer.

Yes it is.Since the square of an integer is called a perfect square, then the square root of a perfect square must be an integer.

No, the square root of 24 is NOT an integer. An integer is a whole number, and the square root of 24 is 4.89897948557.

The integer is 10.

The square root of 4 is 2 (and -2) and is an integer.

an integer

-8

No it is not.

Yes, a perfect square is a number that has an integer square root.

The square of that integer.