-- If the square root is an integer, then add ' 1 ' to it. -- If the square root is not an integer, then there isn't any.
The square root of 4 is 2 (and -2) and is an integer.
Yes, the square root of 121 is 11
No.
The principal square root of 9, the positive integer which is the square root of the number, is 3.
Yes it is.
No it is a complex number the number 10i, which has an integer part (10) and an imaginary part (i), where i=square root of -1
The square root of an integer is a CYCLOTOMIC integer.
No. However, the square root of any positive integer that is NOT a perfect square, IS irrational.
Yes because the square root of a 100 is 10 which is a rational number
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
Why not try it out? See if you can find an integer which, when squared, gives you 100. Or: use a calculator and calculate the square root of 100. If you get an integer, then the answer to the question is "yes"; otherwise the answer is "no".
The square roots of 100 are +10 and -10 . They're both integers.
The square root of 3 is not an integer.
No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106
No, the square root of an integer will not always be an integer. It may or may not be. The square root of nine is three, both of which are integers. The square root of two is not an integer. In fact, it is not even a rational number.