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Square root of x7

Updated: 4/28/2022
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14y ago

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√x7 = (x7)1/2 = x7/2 ≡ x3.5

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Related questions

How do you simplify the square root of x to the seventh power?

sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5


How do you find out what x represents in the equation x to the power of 7 eqals 12?

x7 = 12 if it was x2 we would square root each side. with x7 we need to fing the seventh root. using a calculator type seven then press the button like a square root but with a small x before it the press 12 to find x Alternative method: Take log 12, divide by 7 then take antilog.


How do you find the square root of a variable with an odd numbered exponent?

The same way as you find the square root with an even-numbered exponent. For example, the square root of x10 is x5. That is, divide the exponent by 2. Similarly, the square root of x7 is x3.5. Once again, you simply calculate one-half of the exponent. If you prefer to express this with integer exponents and square roots, in this example you can write x3.5 as x3x0.5. The second part, x0.5, is equivalent to the square root of "x".


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There are infinitely many of them. They include square root of (4.41) square root of (4.42) square root of (4.43) square root of (4.44) square root of (4.45) square root of (5.3) square root of (5.762) square root of (6) square root of (6.1) square root of (6.2)


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It's not a square if it has no root. If a number is a square then, by definition, it MUST have a square root. If it did not it would not be a square.


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The principal square root is the non-negative square root.