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x + 1/x = 2 x + 1/x - 2 = 0 x2 - 2x + 1 = 0 ( x - 1 )( x - 1 ) = 0 x = 1
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Can some one translate the sum of a number and twice the its reciprocal is 3?
A number . . . ' x 'Its reciprocal . . . 1/xTwice its reciprocal . . . 2/xThe sum of (the number) and (twice its reciprocal) . . . x + 2/xThe equation:x + 2/x = 3Multiply each side of the equation by 'x' :x2 + 2 = 3xSubtract 3x from each side:x2 - 3x + 2 = 0Factor the left side, in order to see what's going on:(x - 1) (x - 2) = 0This is true if 'x' is either ' 1 ' or ' 2 '.x = 1The sum of the number and twice its reciprocal . . . 1 + 2/1 = 3X = 2The sum of the number and twice its reciprocal . . . 2 + 2/2 = 3
What is the math property when you are multiplying a reciprocal to equal 1?
== The sum of any number and zero is that number.(2+0== 2) == the sum of any number and zero is that number. (2+0=2)
What does find the repirocal of each number mean?
Say, find the reciprocal of 2 = 1/2 Reciprocal of 1/2 = 2
What is the reciprocal of two?
The reciprocal of 2 is 1/2 (one-half). The reciprocal of any number is 1/number. Simply stated: The reciprocal of any number is the inverse of that number. Let some number, any number, be represented by 'a'. The reciprocal of 'a' is 1/'a'.
The sum of two numbers is 10 and their product is 20 find the sum of the reciprocal of the number?
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
The reciprocal of a number plus the reciprocal of twice the number equalsone half Find the number?
The reciprocal of a number plus the reciprocal of twice the number equals Find the number. 1/2 find the number
Can some one translate the sum of a number and twice the its reciprocal is 3?
A number . . . ' x 'Its reciprocal . . . 1/xTwice its reciprocal . . . 2/xThe sum of (the number) and (twice its reciprocal) . . . x + 2/xThe equation:x + 2/x = 3Multiply each side of the equation by 'x' :x2 + 2 = 3xSubtract 3x from each side:x2 - 3x + 2 = 0Factor the left side, in order to see what's going on:(x - 1) (x - 2) = 0This is true if 'x' is either ' 1 ' or ' 2 '.x = 1The sum of the number and twice its reciprocal . . . 1 + 2/1 = 3X = 2The sum of the number and twice its reciprocal . . . 2 + 2/2 = 3
What is the math property when you are multiplying a reciprocal to equal 1?
== The sum of any number and zero is that number.(2+0== 2) == the sum of any number and zero is that number. (2+0=2)
What does find the repirocal of each number mean?
Say, find the reciprocal of 2 = 1/2 Reciprocal of 1/2 = 2
How do you find the reciprocal of a negative number?
A number multiplied with it's reciprocal must be one. So for example if you have -(1/2), than it's reciprocal is -2.
The sum of two numbers is 10 and their product is 20 find the sum of the reciprocal of the number.?
1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.
What it the reciprocal of 2?
A reciprocal is of a number is 1/number.The reciprocal of 2 is 1/2 = 0.5
What is the reciprocal of two?
The reciprocal of 2 is 1/2 (one-half). The reciprocal of any number is 1/number. Simply stated: The reciprocal of any number is the inverse of that number. Let some number, any number, be represented by 'a'. The reciprocal of 'a' is 1/'a'.
The sum of two numbers is 10 and their product is 20 find the sum of the reciprocal of the number?
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
How do you find the reciprocal of onehalf?
To find the reciprocal of a fraction, you turn it upside down. So the reciprocal of 1/2 is 2/1, or just 2.
Find the reciprocal 2 7?
The reciprocal of 2/7 is 7/2.
What positive number added to its reciprocal gives the minimum sum?
Let x be the positive number we're looking for. The sum of x and its reciprocal is: x + 1/x We want to find the value of x that minimizes this sum. One way to do this is to use calculus. We can take the derivative of the sum with respect to x, set it equal to zero to find the critical points, and then test those points to see which one gives the minimum value. The derivative of the sum is: 1 - 1/x^2 Setting this equal to zero and solving for x, we get: x^2 = 1 x = 1 or x = -1 (but we discard this solution since we are looking for a positive number) So, the minimum sum occurs when x = 1. Checking, we have: 1 + 1/1 = 2 This is the minimum possible value of the sum. Therefore, the positive number we're looking for is 1.
